A 0.6006-g sample of Ni/Cu condenser tubing was dissolved in acid and diluted to 100 mL in a volumetric flask.  Titration of both ions in a 25.0ml aliquot of this solution required 45.81 mL of 0.052285M EDTA.  Mercaptoacetic acid and NH3 were then introduced; production of the Cu complex with the former resulted in the release of an equivalent amount of EDTA, which required 22.85ml titration with 0.07238M Mg2+.  Calculate the %Ni (59.693 g/mol) in the alloy.

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter17: Complexation And Precipitation Reactions And Titrations
Section: Chapter Questions
Problem 17.31QAP
icon
Related questions
Question

A 0.6006-g sample of Ni/Cu condenser tubing was dissolved in acid and diluted to 100 mL in a volumetric flask.  Titration of both ions in a 25.0ml aliquot of this solution required 45.81 mL of 0.052285M EDTA.  Mercaptoacetic acid and NH3 were then introduced; production of the Cu complex with the former resulted in the release of an equivalent amount of EDTA, which required 22.85ml titration with 0.07238M Mg2+.  Calculate the %Ni (59.693 g/mol) in the alloy.

Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Complexometric Titrations
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Fundamentals Of Analytical Chemistry
Fundamentals Of Analytical Chemistry
Chemistry
ISBN:
9781285640686
Author:
Skoog
Publisher:
Cengage