A 0.704 g of a pure acid, HA, is dissolved in water and an acid-base indicator added. The solution requires 33.78 mL of 0.256 M NaOH solution to reach the end point. What is the molar mass of the acid? HA(aq) + NaOH(aq) ⟶ NaA(aq) + H2O(aq) Group of answer choices A.) 81.4 g/mol B.) 20.0 g/mol C.) 199 g/mol D.) 145 g/mol
A 0.704 g of a pure acid, HA, is dissolved in water and an acid-base indicator added. The solution requires 33.78 mL of 0.256 M NaOH solution to reach the end point. What is the molar mass of the acid? HA(aq) + NaOH(aq) ⟶ NaA(aq) + H2O(aq) Group of answer choices A.) 81.4 g/mol B.) 20.0 g/mol C.) 199 g/mol D.) 145 g/mol
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter4: Stoichiometry: Quantitative Information About Chemical Reactions
Section4.8: Stoichiometry Of Reactions In Aqueous Solution-titrations
Problem 4.10CYU: A 25.0-mL sample of vinegar (which contains the weak acid acetic acid, CH3CO2H) requires 28.33 mL of...
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A 0.704 g of a pure acid, HA, is dissolved in water and an acid-base indicator added. The solution requires 33.78 mL of 0.256 M NaOH solution to reach the end point. What is the molar mass of the acid?
HA(aq) + NaOH(aq) ⟶ NaA(aq) + H2O(aq)
Group of answer choices
A.) 81.4 g/mol
B.) 20.0 g/mol
C.) 199 g/mol
D.) 145 g/mol
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