A 1.068 g as received representative sample of fish. Before ignition, moisture was determined to be 5.65%. After ignition, the ashed sample registered 0.2685 g (ashed sample + crucible). The constant weight of crucible was 0.0178 g. From the data given, calculate % ash in the as received sample.
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A 1.068 g as received representative sample of fish. Before ignition, moisture was determined to be 5.65%. After ignition, the ashed sample registered 0.2685 g (ashed sample + crucible). The constant weight of crucible was 0.0178 g. From the data given, calculate % ash in the as received sample.
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- A 5.000-g soil sample was analyzed for potassium content by extracting the potassium using 10.00 mL aqueous ammonium acetate solution. Following the extraction, the soil was filtered and rinsed. The filtrate with rinsings was diluted to exactly 50.00 mL. Then, 1.00 mL of this solution was diluted to 25.00 mL, and this dilution was tested with an instrument. The concentration in this 25.00 mL was found to be3.18 ppm. What is the concentration of the potassium in the soil in ppm?Several steps can be done in preparing samples for analysis with high moisture content except ____________. Group of answer choices The moisture present in the sample is removed before weighing the analytical sample. The analysis is immediately carried out on the wet sample. The moisture content of the sample is determined immediately upon receipt of the sample. The analysis is carried out on the dried sample after the moisture content is determined.Write down the flow chart of Hand molding process for the manufacturing of suppositories? Please answer at your own words.
- Prior to fat analysis, two samples: Sample 1 and Sample 2 with the initial weight for each sample=2.50g. After pre-dried, samples were grinded and reweighted; s1-2.15g and s2=2.11g. Samples were placed in dried glass wool in each thimble and placed extractor for 4-5 hours. Samples were then dried and cooled in desiccators before another weight recorded. The weight for s1=93.51g and for s2=93.78g #Weight of round bottom flask (with glass wool+ thimble) (g) = 92.00 #Weight of round bottom flask (g) =91.00 1) Calculate the percentage of dried fat in s1 2) Calculate the percentage of dried fat in s2. 3) Sample 3 have dried fats of 50%. Identify the correct sequence from the highest to the lowest % of dried fats in sample.Grain sample was found to contain 6.6% moisture. A 5.3000 g as received sample was placed ina crucible (29.5033g tare) . The ashed crucible weighed 30.0055 g.Calculate % ash on a) as received basis b) dry basisA sample of fried potatoes weighing 200 g was extracted using a volatile organicsolvent. The recovered cooking oil weighed 15 g. What methods from thisexperiment could be used to separate the cooking oil after the extraction? (evaporation, gravity filtration or vacuum filtration?) why so?
- Which among the options for minimzing errors (Separation, Saturation-Mix Modification-Masking, Dilution and Matrix Matching, Internal Standard Methods, Standard Addition Methods) is most helpful with more advantages than disadvantages?Ash was estimated in the sample of hay, and the records were as follows, note that the moisture is 18%. Weight of crucible = 14 g Weight of crucible + sample = 15.2 g Weight of crucible + ash = 14.1 g Calculate: i. Ash percentage according to the fresh material ii. Ash percentage according to the dry matter iii. Organic matter percentage according to the dry matter iv. Organic matter percentage according to the fresh materialCalculate the bulk density of a 110 cm3 soil sample that has a 25 percent water content (gravimetric or mass basis) and weighs 150 g.
- You finish doing an experiemnt with Benzoin. These are the results you get:Boiling start point: 137 ceciusBoiling end point: 130 ceciusVile while empty (with cap on): 15.348Vile with crude prod (with cap on: 15.748 Your starting weight: 1.00115.748 - 15.348 = 0.400 / 1.001 = 0.3996 or 39.96% YieldAnswer the following questions with this information:Initial Mass of impure sample:Mass of recrystallized benzoin:Percent reccovery of Benzoin:Melting pot range of purified benzoin:Literature melting point for benzoin:5.00 mL of stock solution is diluted to 25.00 mL, producing solution ALPHA. 10.00 mL of solution ALPHA is diluted to 25.00 mL, resulting in solution BETA. 10.00 mL of solution BETA is then diluted to 25.00 mL, producing solution GAMMA. dilution factor for ALPHA from stock solution = 0.167 dilution factor for BETA from ALPHA solution = 0.0476 part c and d?https://www.bartleby.com/questions-and-answers/excellent-combinations-of-hardness-strength-and-toughness-are-obtained-from-bainite.-one-heat-treate/7672e35d-6282-42a9-a62a-13fc93f02d0a