A 1.70 m by 2.60 m footing has its base 1.70 m below the ground surface. GWT is a meter aboveits base. (L along x-axis)Y = 15.75 kN/mC= 15 kPaYut = 19 kN/m=26°Using Meyerhof's formula, determine the net ultimate load that the footing could carry if e = 0.45m and es = 0.30 m.PLEASE MAKE YOUR HANDWRITINGREADABLE AND CLEAR. THANK YOU SOMUCH :)

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A 1.70 m by 2.60 m footing has its base 1.70 m below the ground surface. GWT is a meter above its base. (L along x-axis) Y = 15.75 kN/m Yu = 19 kN/m C= 15 kPa =26 Using Meyerhof's formula, determine the net ultimate load that the footing could carry if e = 0.45 m and en = 0.30 m.

A 1.70 m by 2.60 m footing has its base 1.70 m below the ground surface. GWT is a meter above its base. (L along x-axis) Y = 15.75 kN/m Yu = 19 kN/m C= 15 kPa =26 Using Meyerhof's formula, determine the net ultimate load that the footing could carry if e = 0.45 m and en = 0.30 m.

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter16: Soil Bearing Capacity For Shallow Foundations

Section: Chapter Questions

Problem 16.16P

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Question

A 1.70 m by 2.60 m footing has its base 1.70 m below the ground surface. GWT is a meter above
its base. (L along x-axis)
Y = 15.75 kN/m
C= 15 kPa
Yut = 19 kN/m
=26°
Using Meyerhof's formula, determine the net ultimate load that the footing could carry if e = 0.45
m and es = 0.30 m.
PLEASE MAKE YOUR HANDWRITING
READABLE AND CLEAR. THANK YOU SO
MUCH :)

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