A 118.1 gram sample of an unknown substance (MM = 189.50 g/mol) is cooled from 233.0 °C to 147.6 °C. (heat capacity of liquid = 1.62 J/g・°C; heat capacity of gas = 1.04 J/g・°C; ∆Hvap = 78.11 kJ/mol; normal boiling point, Tb = 160.3 °C)   How much energy (

Chemistry: The Molecular Science
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Chapter4: Energy And Chemical Reactions
Section: Chapter Questions
Problem 107QRT: The specific heat capacity of copper is 0.385 J g1 C1, whereas it is 0.128 J g1 C1 for gold. Assume...
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A 118.1 gram sample of an unknown substance (MM = 189.50 g/mol) is cooled from 233.0 °C to 147.6 °C. (heat capacity of liquid = 1.62 J/g・°C; heat capacity of gas = 1.04 J/g・°C; ∆Hvap = 78.11 kJ/mol; normal boiling point, Tb = 160.3 °C)
 
How much energy (in kJ) is absorbed/released to cool the gas?
 
 
How much energy (in kJ) is absorbed/released to condense the gas?
 
 
How much energy (in kJ) is absorbed/released to cool the liquid?
 
 
What is the total amount of energy that must be absorbed/released for the entire process?
 
 
 
 
 
 
 
 
 
 
 
Expert Solution
Step 1

The question is based on the application of Hess law.

it states that Net energy change for process remains same, whether it takes place into single step or multiple steps.

this is based on law of conservation of energy.

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