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A 250.0-mL sample of 0.125 M Na3PO4 is mixed with 250.0 mL of 0.175 M Ca(NO3)2 to form Ca3(PO4)2. The net ionic equation for the reaction is given below: 3 Ca2+(aq) + 2 PO43–(aq) ➜ Ca3(PO4)2(s) What is the concentration of the excess reactant ion in the resulting solution assuming that the volumes are additive?   a.4.17 × 10–3 M PO43– b.9.38 × 10–3 M Ca2+ c.5.83 × 10–2 M PO43– d.2.5 × 10–2 M Ca2+

A 250.0-mL sample of 0.125 M Na3PO4 is mixed with 250.0 mL of 0.175 M Ca(NO3)2 to form Ca3(PO4)2. The net ionic equation for the reaction is given below: 3 Ca2+(aq) + 2 PO43–(aq) ➜ Ca3(PO4)2(s) What is the concentration of the excess reactant ion in the resulting solution assuming that the volumes are additive?   a.4.17 × 10–3 M PO43– b.9.38 × 10–3 M Ca2+ c.5.83 × 10–2 M PO43– d.2.5 × 10–2 M Ca2+

General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter4: Chemical Reactions
Section: Chapter Questions
Problem 4.94QP
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A 250.0-mL sample of 0.125 M Na3PO4 is mixed with 250.0 mL of 0.175 M Ca(NO3)2 to form Ca3(PO4)2. The net ionic equation for the reaction is given below:

3 Ca2+(aq) + 2 PO43–(aq) ➜ Ca3(PO4)2(s)

What is the concentration of the excess reactant ion in the resulting solution assuming that the volumes are additive?

 
a.4.17 × 10–3 M PO43–
b.9.38 × 10–3 M Ca2+
c.5.83 × 10–2 M PO43–
d.2.5 × 10–2 M Ca2+
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