A 50.0 mL aliquot of solution contairing 0.450 g of MgSO4 (FM 120.37) in 0.500L required 37.6 mL of EDTA solution for titration. How many mi.ligrams of CaCO3 (FM 100.09) will react with 1.00 mL of this EDTA solution?
Q: An EDTA solution is standardized against a solution of primary standard CaCO3 (0.5622 g dissolve in…
A: We know that, Concentration(M) = moles/volume in L And Number of moles = mass/molar mass
Q: A 50.00-mL aliquot of solution containing 0.358 of MgSO4 (FM 120.37) in 0.500 L required 38.08 mL of…
A: Solution - According to the question - Given - Total Moles of Mg2+ = moles of MgSO4 = mass/molar…
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Q: 11) What is the pM in a titration of 20.0 mL of 0.05 M Ca2 with 0.05 M EDTA if the titration is…
A:
Q: What is the value of pMg for 50.0 ml of a 0.0500 M Mg*2 solution buffered at pH 10.00 and titrated…
A: Question is based on the concept of quantitative analysis. We have to calculate P value of magnesium…
Q: A 50.00-mL aliquot of solution containing 0.395 of MgSO4 (FM 120.37) in 0.500 L required 39.55 mL of…
A:
Q: A 10 mL of a chloride sample was treated with 15 mL of 0.1182 M AgNO3 The excess silver was titrated…
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Q: You took 25.00 mL of unknown water solution and titrated it with EDTA. The EDTA solution molarity…
A: Interpretation: a) To calculate g of CaCO3 in water if total hardness of water is due to CaCO3. b)…
Q: A CaCO3 solution that will be used to standardize EDTA was prepared by dissolving 3.1251 g of solid…
A: Given data; Mass of solid CaCO3 is 3.1251 g The volume of dilute HCl for prepare CaCO3 solution is…
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Q: EDTA Titer A 500.0 mL standard solution of CaCO3 (1.93 g; FM = 100.09) was prepared. Calculate the…
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A: The solution is given below -
Q: In the titration of 50.0 ml of 0.005 M Ca2+ with 0.01 M EDTA ,at pH 10 find the pCa at equivalence…
A: Given, Volume of Ca2+ = 50.0 mLMolarity of Ca2+ = 0.005 MMolarity of EDTA = 0.01 MpH = 10KCaY=…
Q: a. A 40.0 mL sample containing 0.0400 M Ni" was titrated with 0.0400 M EDTA at pH 11.0. Given pkyy…
A: "Since you have asked multiple questions, we will solve the first question for you. If you want any…
Q: Standardization of EDTA was done using MgSO4 standard wherein a 50-mL aliquot of solution obtained…
A: Mass of MgSO4 = 0.480 g in 500 mL (0.500 L) Volume of MgSO4 = 50 mL Volume of EDTA = 39.4 mL Mass…
Q: C1. A carefully weighed 280mg Calcium carbonate was used in the standardization of an EDTA solution.…
A:
Q: (a) A supplement tablet containing about 300.00 mg of calcium ion was dissolved, filtered, and…
A: [EDTA] = 0.0100 M Volume of titration volume of EDTA =…
Q: 2. Chloride in a brine solution NaCI (FM: 58.44) could be determined by the Volhard method. A…
A:
Q: f 5.85 mL of 0.00832 M EDTA solution were needed to titrate a 0.0225 L water sample to an Eriochrome…
A: Balanced reaction is : Ca2+ + EDTA4- ===> [Ca-EDTA]2-
Q: A foot powder sample containing Zn was dissolved on 50.00 mL water and was titrated to the end point…
A:
Q: A CaCO3 solution that will be used to standardize EDTA was prepared by dissolving 3.1251 g of solid…
A: Given data contains, Mass of solid CaCO3 is 3.1251g. Volume of dilute hydrochloric acid for…
Q: Q2: Consider the titration of 30.C ml of 0.015 0 M MnSO with 0.010 0 M EDTA in a salution butfered…
A: To solve the titration curve, we first need to calculate the conditional formation constant of the…
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Q: solution was prepared by dissolving about 3.0 g of NaH2Y2·2H2O in approximately 1 L of water and…
A: At equivalence point, V1× S1 = V2 × S2 Where V1 and V2 are the initial and final volume…
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A: Concentration of CN- can be determined from the amount of Ni2+ used in the titration of CN-.
Q: What is the value of pMg for 50.0 ml of a 0.0500 M Mg*2 solution buffered at pH 10.00 and titrated…
A: The question is based on the concept of equilibrium . we have to calculate P value of magnesium ion…
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Q: What is the value of pMg for 50.0 ml of a 0.0500 M Mg2 solution buffered at pH 10.00 and titrated…
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Q: A 370.00 mL solution of 0.00190 M AB5 is added to a 200.00 mL solution of 0.00165 M CD2. What is…
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Q: 2. A river water sample was titrated against 0.0250 M EDTA to test its hardness of 0.0250 M EDTA. A…
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Q: 25.00 mL of 0.041 32 M Hg2(NO3)2 were titrated with 0.057 89 M KIO3. Hg++ 2103 →→ Hg₂(103)2(s)…
A: Since you have asked a question with multiple sub-parts, as per our company guidelines we are…
Q: Assuming that the concentration of EDTA for the experiment was 0.01 M in 20 ml tap water and the…
A: 1. For total Mg2+ and Ca2+ Volume of EDTA added during titrations are as follows: 1st titration:…
Q: Back titration. Impure K2S2O8 (FM 270.32, 0.507 3 g) was analyzed by treatment with excess standard…
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Q: Titration of Ca2+ and Mg2+ in a 50.00 mL sample of hard water required 23.65 mL of 0.01205 M EDTA. A…
A:
Q: A foot powder sample containing Zn was dissolved on 100.00 mL water and was titrated to the end…
A: Given, Volume of water = 100mL Volume of EDTA = 22.57 mL Molarity of EDTA = 0.01639 M pH =4 α4=3.61…
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