0.5 mg sample required 20.5 ml. EDTA for titration. The EDTA was standardized by titrating 25 ml. of 0.01M CaCl2 solution, requiring 30 ml. EDTA. Calculate Al203 in the sample.
Q: A 50.00-mL aliquot of solution containing 0.358 of MgSO4 (FM 120.37) in 0.500 L required 38.08 mL of…
A: Solution - According to the question - Given - Total Moles of Mg2+ = moles of MgSO4 = mass/molar…
Q: For the titration of 50.00 mL of 0.000226 M Ba²* with 0.100 M EDTA at pH 10.00, ay = 0.30, and Kf =…
A:
Q: Calculate the pSr value for 10 mL of EDTA in the titration of 50 mL of 0.02 M Sr2 + in an…
A: Concentration of Sr2+ 0.02 M. Volume of Sr2+ is 50 mL=0.050 L Moles of Sr2+: nSr2+=MSr2+VSr2+…
Q: Calculate pAl when 25 mL of 0.0274 M Al3+ solution was titrated with 28 mL 0.0180 M EDTA at pH 5.…
A: 25 mL of 0.0274 M Al3+ solution was titrated with 28 mL of 0.0180 M EDTA at pH 5 .log Kf = 16.4…
Q: C- Al is determined by titrating with EDTA Al +H;Y AIY +2H 0.5 mg sample required 20.5 ml. EDTA for…
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Q: Calculate the concentration of Ni2+ in a solution that was prepared by mixing 40.00 mL of 0.0400M…
A: Given data: Volume of Ni2+ = 40 mL Concentration of Ni2+ = 0.04 M Volume of EDTA = 30 mL…
Q: 150.0 mL sample of 0.080 M Ca is titrated with 0.080 M EDTA at pH 9.00. The value of log K for the…
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Q: A 47.00 ml aliquot from a 0.490 L solution that contains 0.410 g of MnSO, (MW = 151.00 g/mol)…
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Q: A deepwell water sample of 100 mL was titrated with 0.010 M EDTA at pH 12 and consumed 31 mL.…
A:
Q: A 49.10 mL aliquot from a 0.500 L solution that contains 0.530 g of MnSO4 (MW=151.00 g/mol) required…
A: Solution -
Q: For the complexiometric titration of Ca2 + ions in the shell of the egg sample weighing 62,576 g,…
A: The question is based on concept of complexometric titration. we have to quantitatively estimate the…
Q: An EDTA solution was prepared by dissolving approximately 4 g of the disodium salt in approximately…
A: Given mass of MgCO3 = 0.07682 g Volume of water = 1 L Molar mass of MgCO3 = 84.31 g/mol
Q: 7. A solution contains 1.569 mg/mL of CoSO4(MM = 155.0 g/mol). Calculate the volume of 0.007840 M…
A: Given data, Q7) Concentration of CoSO4 = 1.569 mg/mL Molar mass of CoSO4 = 155.0 g/mol Concentration…
Q: A 60.00 mL of buffered solution (pH 10) containing Zn2* and Ni2* ions (from a chip sample) is…
A: Metal ion combine with EDTA in 1 : 1 mole ratio. So we would calculate moles of both metal ions…
Q: Standard CaCO, is used to standardize the EDTA solution prior to titration. Suppose 0.385 g of CaCO,…
A:
Q: Calculate the concentration of Ni2+ in the solution prepared by mixing a) 50 mL 0.03 M Ni2+ with…
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Q: Determine the molar concentration of an EDTA solution of which 26.44 mL were required to titrate a…
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Q: Titration of Ca2+ and Mg2+ in a 50.00 mL sample of hard water required 23.65 mL of 0.01205 M EDTA. A…
A:
Q: An EDTA solution is standardized against high-purity CaCO3 by dissolving 0.3982 g CaCO3 in…
A: Given, CaCO3=0.3982 g Volume of EDTA =38.26 mL molecular weight of EDTA= 292.24 g/mol
Q: Write the involved chemical reactions for this: An EDTA solution was prepared by dissolving…
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Q: A solution was prepared by dissolving about 30.00m g of EDTA in approximately 1 L of water and…
A: The solution is given below -
Q: For complexometric titration of Ca (II) ions in the shell of an egg sample weighing 59,427 g, the…
A: From the result of complexometric titration, concentration of Ca2+ in the egg shell has to be…
Q: The hardness of a water sample may be determined by titrating a 100-mL sample of water with 0.010 M…
A: The above question can be solved using the formula M1V1= M2V2
Q: A deepwell water sample of 100 mL was titrated with 0.010 M EDTA at pH 12 and consumed 31 mL.…
A:
Q: . The Tl in a 9.57 g sample of rodenticide was oxidized to the trivalent state and treated with an…
A: The question is based on the concept of quantitative analysis. We have to quantitatively estimate…
Q: For the titration of 20.0 mL of 0.0100 M EDTA with 50.0 mL of 0.0200 M MNPO4 at pH = 10.00,…
A: The given information is: Volume of EDTA = 20.0ml Molarity of EDTA= 0.010 M Volume of MnPO4 = 50.0ml…
Q: A 25.00 mL sample of water, buffered at a pH of 10, is titrated with 0.008989 M EDTA using the…
A: The hardness in water can be calculated using EDTA which binds with metal ions like Ca and Mg.
Q: (a) A supplement tablet containing about 300.00 mg of calcium ion was dissolved, filtered, and…
A: [EDTA] = 0.0100 M Volume of titration volume of EDTA =…
Q: f 5.85 mL of 0.00832 M EDTA solution were needed to titrate a 0.0225 L water sample to an Eriochrome…
A: Balanced reaction is : Ca2+ + EDTA4- ===> [Ca-EDTA]2-
Q: A water sample was tested for water hardness. A 50.00 mL sample, prepared and buffered to pH 10,…
A: a. At the pH = 10, EDTA form complex with both Ca2+ and Mg2+ ion and the total hardness of water is…
Q: In the titration of 50 mL 0.02 M Sr² with 0.02 M EDTA in a buffered medium at titrated pH 11,…
A: EDTA is ethylenediaminetetraacetic acid which is an indicator which complexes with the metal ions…
Q: 3. A solution contains 1.694 mg of CoSo. (155.0 g/mol) per milliliter. a. Calculate the volume of…
A: a) Amount of CoSO4 = 1.694 mg/mL Calculation of mass of CoSO4: Mass=1.694 mg mL-1×25 mL=42.35 mg…
Q: A sample of pure CaCO3 weighing 0.2428g is dissolved in HCI acid and the solution diluted to 250.0ml…
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Q: The Cl– content of a solution was analyzed via an EDTA titration. 2.00 g of AgNO3 was added to 25.00…
A: It is an example of back titration. In such type of titration, two titrants are present, out of…
Q: Titration of 50.00 mL of 0.04715 M Na2C2O4 required 39.25 mL of a potassium permanganate solution.…
A: Given, Volume of Na2C2O4 = 50.00 mL Concentration of Na2C2O4 = 0.04715 M…
Q: In a solution kept constant by buffering to pH= 8.0, 50.0 mL of 0.0050 M Ni2+ is 0,0100 İn titration…
A: The question is based on the concept of quantitative analysis. We have to calculate pNi at different…
Q: The cadmium and lead ions in a 50.00 mL sample required 40.09 mL of a 0.005000 M EDTA for titration.…
A:
Q: chip sample) is analyzed using EDTA titration with EBT as indicator. The following data were…
A:
Q: For the complexiometric titration of Ca2 + ions in the shell of the egg sample weighing 62,576 g,…
A:
Q: Standard CaCO3 is used to standardize the EDTA solution prior to titration. Suppose 0.385 g of CaCO,…
A: Given that, Mass of CaCO3 = 0.385 g Number of moles of CaCO3 = Mass of CaCO3Molar mass of CaCO3=…
Q: Repeats of 12.64 mL samples of a 0.2937 M primary standard zinc ion solution were titrated with an…
A: Given that - Volume of standard zinc ion Solution = 12.64 mL Molarity of standard zinc ion…
Q: A 5.00 mL tap water sample was measured out with a volumetric pipette, and added to a 25 mL…
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Q: At pH 7, what metal ions can be titrated by EDTA?
A: In complexometric titrations, EDTA requires a certain minimum pH for titrating each metal ion. The…
Q: fön in a 25.00-mL sample was converted to dicyanoargentate (l) ion by the addition of a xcess…
A:
Q: 50 mL of a solution of 0.0200 M Zn2+ will be titrated with 0.0100 M EDTA in 0.0100 M NH3 at pH…
A: given values = K1 = 1.02 x 10-2, K2= 2.14 x 10-3, K3 = 6.92 x 10-7 and K4 = 5.50 x 10-11. pH = 6.0
Q: To a 50.00-mL aqueous solution containing Pb2+ is added a total amount of 5.000 mmol EDTA. The pH…
A: This is a method of quantitative estimation of concentration of unknown solution by titrating it…
Q: A solid sample containing chloride and with a mass equal to 6.000 g was dissolved in water and…
A: Balanced chemical equation for the given reaction is: Cl- + AgNO3 → AgCl + NO3- This means that 1…
Q: Titration of Ca2+ and Mg2+ in a 50.00 mL sample of hard water required 23.65 mL of 0.01205 M EDTA. A…
A:
Q: A 50.0ml sample of water containing both Ca+2 and Mg+2 is titrated with 16.54ml of 0.01104M EDTA in…
A: Calculation of total mol of EDTA used: nEDTA=Molarity×Volume=0.01104 mol/L×16.54×10-3 L=1.826×10-4…
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- The accompanying data (1.00-cm cells) were obtained for the spectrophotometric titration 10.00 mL of Pd(II) with 2.44 10-4 M Nitroso R(O. W Rollins and M. M. Oldham, Anal. chem .,1971, 43, 262, DOI: 10.1021/ac60297a026). Calculate the concentration of the Pd(II) solution, given that the ligand-to-cation ratio in the colored product is 2:1Sketch a photometric titration curve for the titration of Sn2+ with MnO4 . What color radiation should be used for this titration? Explain.A solid containing tris was dissolved in water and brought to a total volume of 50.00 ml. A 10.00 ml aliquot of the solution was titrated with 0.09978 M HCl to a bromcresol green endpoint. The aliquot consumed 38.93 ml of titrant. Calculate the weight of tris in the original sample.
- The cadmium and lead ions in a 50.00 mL sample required 40.09 mL of a 0.005000 M EDTA for titration. A 75.00 mL portion of the same sample was made basic and treated with excess KCN masking the cadmium as Cd(CN)42-. This solution required 21.42 mL of the EDTA for titration. Calculate the concentration of Cd2+ and Pb2+ in the sample ppm and in M.A volume of 50.00 ml of 0.01800 mol L-1 EDTA solution was added to a solution containing 0.02550 g of Ni. The unreacted excess of EDTA was then titrated with V mL 0.01500 mol L-1 ZnSO4 solution. Calculate the value of V. Data: Ni = 58.69 EDTA = 292.24Chromel is an alloy composed of nickel, iron and chromium.A 0.6472 g sample was dissolved and diluted to 250 mL. When a50 mL aliquot of 0.05182 M EDTA was mixed with an equal volumeof the diluted sample and all the three ions were chelated, a 5.11 mLback titration with 0.06241 M copper (II) was required.The chromium in a second 50 mL aliquot was masked through theaddition of hexamethylenetetramine, titration of the Fe and Nirequired 36.28 mL of 0.05182 M EDTA.Iron and chromium were masked with pyrophosphate in a third50 mL aliquot and the nickel was titrated with 25.91 mL of theEDTA solution.Calculate the percentage of nickel, chromium and iron in thealloy.
- A solution was prepared by dissolving about 30.00m g of EDTA in approximately 1 L of water and standardizing against 50.00-mL aliquots of 0.004356 M Mg2+. An average titration of 32.65 mL was required. Calculate the molar concentration of the EDTA.A 0.5745 g sample of an alloy containing principally bismuth and lead is dissolved in nitric acid and diluted to 250.0 mL in a volumetric flask. A 50.00 mL aliquot is withdrawn, the pH adjusted to 1.5, and the bismuth titrated with 30.26 mL of 0.01024 M EDTA. The pH of the solution is then increased to 5.0 and the lead titrated with 20.42 mL of the same EDTA solution. Calculate the percentages of lead and bismuth in the alloy.0.8153 g of a sample containing Pb(NO3)2 was taken, dissolved in water, and 40.20 mL of 0.06 M EDTA was added. What is the percentage of Pb(NO3)2 since the excess EDTA is back-titrated with 23.10 mL of 0.02 M EDTA? (Pb(NO3)2: 331 g/mol, Pb: 207 g/mol)
- c. An EDTA solution is standardized against high-purity CaCO3 by dissolving 0.3982 g CaCO3 in hydrochloric acid, adjusting the pH to 10 with ammoniacal buffer, and titrating. If 38.26 mL was required for the titration, calculate the molarity of the EDTA. (Molecular weight EDTA = 292.24 g mol-1)A solid sample containing chloride and with a mass equal to 6.000 g was dissolved in water and transferred to a 100.0 ml flask. A 50.0 mL aliquot of this solution was diluted to 250.0 mL. In the titration of 20.0 mL of the diluted solution, 32.0 mL of 0.2000 mol L-1 AgNO3 standard solution were used. Calculate the % of impurities in the analyzed sample. Data: Cl = 35.45Determinethe concentration of an EDTA solution given that a 20.00 mLsample of 0.02491M Zn2+was titrated with37.84mL of EDTA