2. Chloride in a brine solution NaCI (FM: 58.44) could be determined by the Volhard method. A 10.00-mL aliquot of the solution was treated with 15.00 mL of standard 0.1182 M AGNO3 (FM: 169.872) solution. The excess silver was titrated with standard 0.101 M KSCN (FM: 97.182) solution, requiring 9.52 mL to reach the red Fe(SCN)2* end point. Calculate the concentration of chloride (AM: 35.453) in the brine solution, in g/L. NaCl(aq) + AgNO3(aq) - AgCl(s) + NANO3(aq) AGNO3(aq)+KSCN(aq)- AGSCN(s) + KNO3(aq)

Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Chapter14: Applications Of Ultraviolet-visible Molecular Absorption Spectrometry
Section: Chapter Questions
Problem 14.6QAP: The accompanying data (1.00-cm cells) were obtained for the spectrophotometric titration 10.00 mL of...
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2. Chloride in a brine solution NaCI (FM: 58.44) could be determined by the Volhard method. A
10.00-mL aliquot of the solution was treated with 15.00 mL of standard 0.1182 M AGNO3 (FM:
169.872) solution. The excess silver was titrated with standard 0.101 M KSCN (FM: 97.182)
solution, requiring 9.52 mL to reach the red Fe(SCN)2 end point. Calculate the concentration of
chloride (AM: 35.453) in the brine solution, in g/L.
NaCl(aq) + AGNO3(aq) - AgCl(s) + NaNO3(aq)
AGNO3(aq)+KSCN(aq) - AGSCN(s) + KNO3(aq)
O 2.877 g/L
O 5.434 g/L
O 3.729 g/L
O 4.581 g/L
Transcribed Image Text:2. Chloride in a brine solution NaCI (FM: 58.44) could be determined by the Volhard method. A 10.00-mL aliquot of the solution was treated with 15.00 mL of standard 0.1182 M AGNO3 (FM: 169.872) solution. The excess silver was titrated with standard 0.101 M KSCN (FM: 97.182) solution, requiring 9.52 mL to reach the red Fe(SCN)2 end point. Calculate the concentration of chloride (AM: 35.453) in the brine solution, in g/L. NaCl(aq) + AGNO3(aq) - AgCl(s) + NaNO3(aq) AGNO3(aq)+KSCN(aq) - AGSCN(s) + KNO3(aq) O 2.877 g/L O 5.434 g/L O 3.729 g/L O 4.581 g/L
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