a) Answer ALL parts a) - c). i) State the selection rule for an IR active transition. What factor influences the intensity of an IR band? ii) With the aid of a diagram, describe the bonding between a CO ligand and a d-block transition metal ion. iii) Explain why [V(CO)6]- has a lower CO stretching frequency than [Mn(CO)]*. iv) Briefly discuss the influence that binding mode (terminal vs bridging) has on the stretching frequency of CO in coordination complexes.
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- By using the given 1) electronic absorption spectrum, 2) the Tanabo-Sugano diagram for d3 complex in octahedral ligand field and 3) the absorption/emission spectra, explain the following: a) Ligand field states (to support your explanation show the filling of the orbitals) b) Radiative transitions (to support your explanation refer to fluorescence, phosphorescence and Stokes’ shift)1,Count up the 18-electron rule of the organometallic complex (Ferrocene) using covalent counting method.2. Draw the molecular orbital diagram for B2 and find the bond order?Blue LED used as illlumination and Yellow LED used as detector. Explain at Molecular basis detail for beer's lambert law the effect of it and what will happen if you will choose this LED color.
- Draw the metal coordination structure of carbonic anhydrase enzyme. Clearly show the 3-Dgeometry round the metal center. *Hi, I am actually confused on what a 3-D geometry of this structure should look like and would like some clarification, Thank You in advance!Scott test is one of the methods used for screening for Cocaine in Forensic Chemistry. The multi step method consists of a) reacting the sample drug with cobaltous thiocyanate b) dissolving of the formed precipitate by adding HCl and c) extraction of coordination compound with Chloroform d) measurement of absorbance of extracted coordination compound at 627 nm All the reactions in this multistep method are not fully understood. However, it was determined that there are 2 moles of cocaine in coordination compound measured in last step. If coordination compound is represented as “Scott” coordination compound, which of the following is correct “stoichiometric” factor to get mass of cocaine from mass of measured complex ? a.g (Scott coordination cpd) * MM (Scott coordination cpd) MM (cocaine) b.g (Scott coordination cpd) * 2 *MM (Scott coordination cpd) MM…A protein binds a ligand with a KD value of 0.25 M. If you are at a ligand concentration of 0.63 M, what is the fraction bound? Please report your answer to two significant figures. There should be no units in your answer
- Discuss the binding mode and geometry of the imido and cyclopentadienyl ligands in the tungsten complex below.the spectrochemical series allows us to explain the variety ofcolors observed in transition metal complexes. But in practice, someone attempting to predictthe properties of compounds can occasionally be frustrated by various complicating factors.For instance, the nitrite ligand is presented as having a high field strength, but that is only whenit is the nitrogen of the nitrite that is coordinating to the metal center. Nitrite is also capable ofbinding to the metal center through an oxygen, and when this happens, nitrite is a low fieldstrength ligand. Furthermore, many metals initially precipitate as simple ionic salts before theyhave a chance to form more soluble complex ions. And occasionally, unexpected redoxreactions can lead to complex mixtures. Despite these complications, the spectrochemical series remains a powerful predictivetool for inorganic chemists. New ligands are being developed all the time, and each new ligandneeds to be placed, at least approximately, on the…the spectrochemical series allows us to explain the variety ofcolors observed in transition metal complexes. But in practice, someone attempting to predictthe properties of compounds can occasionally be frustrated by various complicating factors.For instance, the nitrite ligand is presented as having a high field strength, but that is only whenit is the nitrogen of the nitrite that is coordinating to the metal center. Nitrite is also capable ofbinding to the metal center through an oxygen, and when this happens, nitrite is a low fieldstrength ligand. Furthermore, many metals initially precipitate as simple ionic salts before theyhave a chance to form more soluble complex ions. And occasionally, unexpected redoxreactions can lead to complex mixtures. The complex that copper forms with chloride ions is tetrahedral. Write the chemical formula for this complex. Thoroughly describe the energy diagram for the d orbitals.
- the spectrochemical series allows us to explain the variety ofcolors observed in transition metal complexes. But in practice, someone attempting to predictthe properties of compounds can occasionally be frustrated by various complicating factors.For instance, the nitrite ligand is presented as having a high field strength, but that is only whenit is the nitrogen of the nitrite that is coordinating to the metal center. Nitrite is also capable ofbinding to the metal center through an oxygen, and when this happens, nitrite is a low fieldstrength ligand. Furthermore, many metals initially precipitate as simple ionic salts before theyhave a chance to form more soluble complex ions. And occasionally, unexpected redoxreactions can lead to complex mixtures. Despite these complications, the spectrochemical series remains a powerful predictivetool for inorganic chemists. New ligands are being developed all the time, and each new ligandneeds to be placed, at least approximately, on the…what about this answer ? Is this also correct? Isn't it contradict? " However, the back-donation from the metal center to CO's empty 2π* orbital is less extensive than with NO. This is because CO's 2π* orbital is higher in energy compared to NO's 2π* orbital. In summary, both NO and CO are pi-acceptor ligands due to their empty 2π* orbitals. However, NO is expected to be a stronger pi-acceptor ligand than CO because of the presence of the unpaired electron in its 2π* orbital and the lower energy of this orbital. The stronger pi-acceptor ability of NO can lead to a more stable metal-ligand bond, as well as greater electron density redistribution between the metal center and the ligand." I'm so confused NO is weaker or stronger pi-acceptor ligandsIn general, would you expect EDTA4- to coordinate to transition metal ions more or less strongly than ethylenediamine does? Justify your answer with a reason other than the different charges on the two ligands.