a block of mass m= 3.20 kg slides from rest a distance d down a frictionless incline at angle u = 30.0 where it runs into a spring of spring constant 431 N/m.When the block momentarily stops, it has compressed the spring by 21.0 cm.What are (a) distance d and (b) the distance between the point of the first block–spring contact and the point where the block’s speed is greatest?

Q: A glider of mass 0.240 kgkg is on a frictionless, horizontal track, attached to a horizontal spring…

A: Potential energy of a spring stretched by some distance 'x' is 12kx2 Kinetic energy is given by the…

Q: In the figure, a 2.7 kg block is accelerated from rest by a compressed spring of spring constant 660…

A: the vertical forces are normal force (up) and gravity force (down).  As Vertical component = 0

Q: Q: A block of mass 0.50 kg is placed on top of a light vertical spring of force constant 7500 N/m…

A:

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Q: Item 15 A 176 g block is launched by compressing a spring of constant k =200N/m a distance of 15 cm.…

A: Given data k =200N/m d =15 cm mue = 0.27 D = 0.85 m

Q: A spring (k = 193.7 n/m) is compressed 1.35 m by a block of mass 5 kg. The system is released from…

A:

Q: An object with mass m = 8.0 kg is released from rest from a height H = 11 m as shown in the figure.…

A:

Q: Problem 7: A small block of mass M = 450 g is placed on top of a larger block of mass 3M which is…

A: Given, Mass= 0.45Kg spring constant, k=2.8N/m maximum length of stretched spring= 4.5 cm =0.045m…

Q: A 2.00-kg block is pushed against a spring with negligible mass and force constant compressing it…

A: The expression to determine the total energy of the block at the top of plane is, Et=Ut+Kt

Q: 75 SSM To form a pendulum, a 0.092 kg ball is attached to one end of a rod of length 0.62 m and…

A: Given that: Mass of the ball,  m=0.092 kgLength of the rod, L=0.62 mMass of the rod, M=0…

Q: In the figure, a block of mass m = 3.30 kg slides from rest a distance d down a frictionless incline…

A: Mass (m) = 3.3kg   θ = 35.0 ˚ ( Angle of inclination)   Spring constant (k)= 450N/m  Compression (x)…

Q: Assume a small box (m = 222 g) slides along a frictionless ¼ circle track of radius R = 1.00O m onto…

A: (1) Apply the conservation of energy between the starting and end of the circular track. Substitute…

Q: As seen in Fig. 1, a 5.00 kg mass starts from rest at the top of a frictionless incline at heighty0=…

A: Work done by gravitational force will be = mgh Work = 5 x 9.8 x 3 = 147 J  Using Work energy…

Q: An object with mass m = 3.0 kg is released from rest from a height H = 10 m as shown in the figure.…

A: Work done by a body to move on the frictional surface from a point to another. While moving the…

Q: An inclined plane of angle e=20° has a spring of force constant k=500 N/m fastened securely at the…

A:

Q: A 2.00-kg block is pushed against a spring with negligible mass and force constant compressing it…

A:

Q: A 1.30 kg block slides on a frictionless horizontal surface until it encounters a spring with a…

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Q: Consider a block of mass 0.270 kg attached to a spring of spring constant 160 N/m. The block is…

A:

Q: k = 50 N/m ell ele 0.5 kg X = -0.5 m X = 0.0 m X = 0.5 m A block of mass 0.5 kg on a horizontal…

A: There are 2 questions being asked. Both of them relate to simple harmonic motion of a block.

Q: A horizontal spring with spring constant 230 N/mN/m is compressed by 10 cmcm and then used to launch…

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Q: A block of mass m = 2.25 kg slides along a horizontal ww table with speed vo = 10.00 m/s. At x = 0,…

A: The mass of the block is m = 2.25 kg. The speed with which the block slides along a horizontal table…

Q: An object with mass m = 5.0 kg is released from rest from a height H = 11 m as shown in the figure.…

A:

Q: Consider a block of mass 0.220 kg attached to a spring of spring constant 120 N/m. The block is…

A: m = 0.220 kg K = 120 N/m x1 = 11.2 cm = 0.112 m

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Q: A block of mass 3.20 kg is placed against a horizontal spring of constant k = 725 N/m and pushed so…

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A: (a) The elastic potential energy of the block spring system is,

Q: If a mass of 0.65 kg is attached to a horizontal spring displaced by 5.5cm, determine the spring…

A: Given Mass is given as m=0.65 kg Displacement of the spring is ∆x=5.5 cm=0.055 m Potential energy…

Q: A block with mass e.50 kg is forced against a horizontal spring of negligible mass, compressing the…

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A:

Q: A hockey puck sliding along frictionless ice with speed ν to the right collides with a horizontal…

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Q: tion between the block and the plane is μk = 0.13. In the initial position, where the spring is…

A:

Q: A 2.50 kg textbook is forced against a horizontal spring of negligible mass and having a spring…

A: Given : m = 2.50 kg k = 250 N/m x = 250 mm = 0.25 m μk = 0.30

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A:

Q: A 2.50-kg block on a horizontal floor is attached to a horizontal spring that is initially…

A: Using work-energy theorem Kf+Uf-Wnc=Ki+Ui0+0+μkmgd=0+12kx2d=kx22μkmg

Q: Mickey, a daredevil mouse of mass 20.3 g,20.3 g, is attempting to become the world's first "mouse…

A: Let v be the velocity of mickey, x be the distance the spring is compressed initially, k is the…

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A:

Q: 14) A block of mass 0.20 kg is against a spring compressed 0.20 m with spring constant 70 N/m. When…

A:

Q: consider a popgun with a spring constant 843 N/m. A projectile of mass 0.06 kg is inserted into the…

A: Apply the conservation of energy between final position (max height) and initial position.

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A: Given: The mass of mouse m = 0.0221 kg. The force constant of spring k = 86.3 N/m compression of…

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A: Given, mass of the block, m = 1.30 kg Force constant, k = 520 Nm compression, x = 2.50 cm

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A:

Q: A box of mass 10 kg slides along a frictionless surface with a velocity of v = 8.0 m/s and hits a…

A:

Q: A block of mass m 2.00 kg slides along a horizontal table with speed vo 9.50 m/s. At x = 0 it hits a…

A: Given:Mass of the block, m = 2.00 kgSpeed of the block, V0 = 9.50 m/sSpring constant, K = 95…

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.