A bob of mass m is attached to a vertical string with length L1. When set into a simple harmonic motion, the bob completes six cycles per second. If the string is replaced with a string of length L2 such that L2 = (L1)/4, then the new frequency of oscillation is: f = 1.5 Hz f = 3 Hz Of=12 Hz Of = 24 Hz der a tension of 80 N. The length of the stretched

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Chapter16: Oscillatory Motion And Waves
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Problem 19PE: Suppose a diving beard wi1h no one on it bounces up and down in a simple harmonic motion with a...
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A bob of mass m is attached to a vertical string with length L1. When set into a
simple harmonic motion, the bob completes six cycles per second. If the string is
replaced with a string of length L2 such that L2 = (L1)/4, then the new frequency of
oscillation is:
f = 1.5 Hz
f = 3 Hz
Of=12 Hz
Of = 24 Hz
der a tension of 80 N. The length of the stretched
Transcribed Image Text:A bob of mass m is attached to a vertical string with length L1. When set into a simple harmonic motion, the bob completes six cycles per second. If the string is replaced with a string of length L2 such that L2 = (L1)/4, then the new frequency of oscillation is: f = 1.5 Hz f = 3 Hz Of=12 Hz Of = 24 Hz der a tension of 80 N. The length of the stretched
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