A brown female (#1) with high cholesterol is mated to a black male (#2) with normal cholesterol. The progeny from this cross include a brown male (#3) with high cholesterol and a black female (#4) with normal cholesterol. Mouse #3 is mated to a brown female (#5) with normal cholesterol. If 4 mice are produced from this cross, what is the probability that all 4 will have brown fur?

A brown female (#1) with high cholesterol is mated to a black male (#2) with normal cholesterol. The progeny from this cross include a brown male (#3) with high cholesterol and a black female (#4) with normal cholesterol. Mouse #3 is mated to a brown female (#5) with normal cholesterol. If 4 mice are produced from this cross, what is the probability that all 4 will have brown fur?

Name: In mice, the trait for high cholesterol is specified by a dominant all
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Description: In mice, the trait for high cholesterol is specified by a dominant allele designatedHC, whereas the wild-type allele for normal cholesterol levels is designated hc.Black fur is specified by a recessive allele designated bl, whereas the wild-typeallel

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter11: Genome Alterations: Mutation And Epigenetics

Section: Chapter Questions

Problem 16QP: Familial retinoblastoma, a rare autosomal dominant defect, arose in a large family that had no prior...

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In mice, the trait for high cholesterol is specified by a dominant allele designated HC, whereas the wild-type allele for normal cholesterol levels is designated hc. Black fur is specified by a recessive allele designated bl, whereas the wild-type allele which gives brown fur is designated BL. The genes for both of these traits are 30cM apart on the same autosome. A brown female (#1) with high cholesterol is mated to a black male (#2) with normal cholesterol. The progeny from this cross include a brown male (#3) with high cholesterol and a black female (#4) with normal cholesterol. What is the probability that the black mouse in the progeny of the first cross will also have high cholesterol?
In Drosophila, the autosomal recessive dp allele ofthe dumpy gene produces short, curved wings, whilethe autosomal recessive allele bw of the brown genecauses brown eyes. In a testcross using femalesheterozygous for both of these genes, the followingresults were obtained:wild-type wings, wild-type eyes 178wild-type wings, brown eyes 185dumpy wings, wild-type eyes 172dumpy wings, brown eyes 181In a testcross using males heterozygous for both ofthese genes, a different set of results was obtained:wild-type wings, wild-type eyes 247dumpy wings, brown eyes 242a. What can you conclude from the first testcross?b. What can you conclude from the second testcross?c. How can you reconcile the data shown in parts (a)and (b)? Can you exploit the difference betweenthese two sets of data to devise a general test forsynteny in Drosophila?d. The genetic distance between dumpy and brown is91.5 m.u. How could this value be measured?
In humans, the glucose-6-phosphate dehydrogenase (G6PD) gene involved in sugar metabolismis X-linked. The dominant allele (G) codes for fast enzymes for normal cell functioning while the recessiveallele (g) codes for slow enzymes, which are responsible for the reduced enzymatic activity of cells.However, the presence of slow enzymes has minimal effect in the overall functioning of heterozygotes,thus normal. Recessives, however, are more prone to oxidative reactions that speed up the celldamaging process, thus weak (but not lethal). If random inactivation occurs during dosage compensation,what would be the genotypes and phenotypes of the children of a heterozygous mother and a recessivefather?
In the fruit fly, recessive mutations in either of two independently assorting genes, brown and purple, prevent the synthesis of red pigment in the eyes. Thus, homozygotes for either of these mutations have brownish-purple eyes. However, heterozygotes for both of these mutations have dark red, that is, wild-type eyes. If such double heterozygotes are intercrossed, what kinds of progeny will be produced, and in what proportions?
. The production of pigment in the outer layer of seedsof corn requires each of the three independently assorting genes A, C, and R to be represented by at leastone dominant allele, as specified in Problem 64. Thedominant allele Pr of a fourth independently assortinggene is required to convert the biochemical precursorinto a purple pigment, and its recessive allele pr makesthe pigment red. Plants that do not produce pigmenthave yellow seeds. Consider a cross of a strain of genotype A/A ; C/C ; R/R ; pr/pr with a strain of genotypea/a ; c/c ; r/r ; Pr/Pr.a. What are the phenotypes of the parents?b. What will be the phenotype of the F1?c. What phenotypes, and in what proportions, willappear in the progeny of a selfed F1?d. What progeny proportions do you predict from thetestcross of an F1?
In humans, a very rare dominant allele that causes the little fingerto be crooked has a penetrance of 80%. In other words, 80% of heterozygotes carrying the allele will have a crooked little finger. If ahomozygous unaffected person has children with a heterozygotecarrying this mutant allele, what is the probability that an offspring will have a little finger that is crooked?
In humans, the genetic disease cystic fibrosis is caused by a recessive allele (a). The normal (healthy) allele is dominant (A). What is the genotype of someone who has cystic fibrosis? What are the two different genotypes that a healthy person could have? If two people were both heterozygous for the cystic fibrosis gene, what fraction of their children would be likely to have this disease? Hint: Draw a Punnett square to figure it out.
In mice, the wild-type coat color, agouti (AA) [left mouse], is dominant to solid-colored, black fur (aa) [middle mouse]. However, a separate gene (C) is necessary for pigment production. A mouse that is homozygous for a recessive c allele at this locus is unable to produce pigment and is albino [right mouse] regardless of the allele present at locus A. Thus, the following genotypes are listed with their associated phenotypes: ~ A/A; C/C or A/A; C/c or A/a; C/C or A/a; C/c ==> "agouti" ~ a/a; C/C or a/a; C/c ==> "black" ~ A/A; c/c or A/a; c/c or a/a; c/c or a/a; c/c ==> "albino" This is an example of recessive epistasis, in which the recessive c allele "stands upon" the possible genotypes for the A gene (A/A, A/a, or a/a). If two agouti mice with the A/a; C/c genotype are mated, what is the expected phenotypic ratio in their offspring? A.9 albino, 4 agouti, 3 black B. 9 agouti, 4 albino, 3 black C.9 black, 4 albino, 3 agouti D.9 agouti, 4 black, 3 albino
Galactosemia is a recessive human disease that istreatable by restricting lactose and glucose in the diet.Susan Smithers and her husband are both heterozygous for the galactosemia gene.a. Susan is pregnant with twins. If she hasfraternal (nonidentical) twins, what is theprobability both of the twins will be girls whohave galactosemia?b. If the twins are identical, what is the probabilitythat both will be girls and have galactosemia?For parts (c–g), assume that none of the children isa twin.c. If Susan and her husband have four children, whatis the probability that none of the four will havegalactosemia?d. If the couple has four children, what is the probability that at least one child will have galactosemia?e. If the couple has four children, what is the probability that the first two will have galactosemia andthe second two will not?f. If the couple has three children, what is the probability that two of the children will have galactosemia and one will not, regardless of order?g. If…
In dogs, black coat color (B) is dominant to yellow coat color (b), and straight fur (C) is dominant to curly fur (c). The coat color gene and the fur texture gene are on different chromosomes, so they assort independently, and are not sex-linked. In a cross between two BbCc parents, given that an offspring has black coat color and straight fur, what's the probability that it is heterozygous for both genes? Give 2 digits past the decimals.
Let’s suppose a recessive allele encodes a completely defective protein. If the functional allele is dominant, what does that tell youabout the amount of the functional protein that is sufficient to causethe phenotype? What if the allele shows incomplete dominance?
This pedigree traces the inheritance of a trait in humans. Based on this pedigree, is the allele for this disease dominant or recessive? Is it sex-linked? Explain. What genotypes are most probable for the individuals labeled 4, 7, and 10?