A certain half-reaction has a standard reduction potential E=+0.51 V. An engineer proposes using this half-reaction at the anode of a galvanic cell that must 'red provide at least 1.10 V of electrical power. The cell will operate under standard conditions. Note for advanced students: assume the engineer requires this half-reaction to happer lo Data Half-Reaction Ag+ (aq) + e Ag (s) Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have? O yes, there is a minimum. = Ov Al3+ (aq) + 3e- → Al (s) %3D "red Aut (ag) + e- - Au (s) If so, check the "yes" box and calculate the minimum. Round your answer to 2 decimal places. If there is no lower limit, check the "no" box. Au3+ (ag) + 3e Au (s) O no minimum Ba2+ (aq) + 2e - - Ba (s) Br2 (1) + 2e- - 2Br (aq) Ca2+ (aq) + 2e Ca (s) Cl2 (9) + 2e - 2CI (aq) Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cl can have? E- Ov O yes, there is a maximum. %3D red Co2+ (aq) + 2e- Co (s) If so, check the "yes" box and calculate the maximum. Round your answer to 2 decimal places. If there is no upper limit, check the "no" box. Co3+ (aq) + e - Co2+ (aq) Cr2+ (aq) + 2e → Cr (s) Cr3+ (aq) + 3e - Cr (s) O no maximum Cr3+ (aq) + e - Cr2+ (aq) Cro42- (aq) + 4H20 (1) + 3e - Cr(OH)3 (s) + 50H (aq) By using the information in the ALEKS Data tab, write a balanced equation describing a half reaction that could be used at the cathode of this cell. Cu2+ (aq) + 2e- Cu (s) Cu2+ (ag) + e- - Cut (aq) Note: write the half reaction as it would Cu* (aq) + e - Cu (s) actually occur at the cathode. F2 (9) + 2e 2F (aq) 2. Fe2+ (aq) + 2e - Fe (s) -0. Fe3+ (aq) + e - Fe2+ (aq) 0. Explanation Check -0. Fe3+ (aq) + 3e Fe (s)

Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter17: Electrochemistry
Section: Chapter Questions
Problem 160MP
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Question
A certain half-reaction has a standard reduction potential E=+0.51 V. An engineer proposes using this half-reaction at the anode of a galvanic cell that must
'red
provide at least 1.10 V of electrical power. The cell will operate under standard conditions.
Note for advanced students: assume the engineer requires this half-reaction to happern lo Data
Half-Reaction
E° (V)
Ag+ (aq) + e- Ag (s)
0.7996
Is there a minimum standard reduction
potential that the half-reaction used at
the cathode of this cell can have?
= Ov
Al3+ (aq) + 3e → Al (s)
O yes, there is a minimum.
%3D
red
-1.676
Au+ (aq) + e - Au (s)
1.692
If so, check the "yes" box and calculate
the minimum. Round your answer to 2
decimal places. If there is no lower
limit, check the "no" box.
Au3+ (aq) + 3e Au (s)
1.498
O no minimum
Ba2+ (aq) + 2e-
+ Ba (s)
-2.912
Br2 (1) + 2e- -
2Br (aq)
1.066
Ca2+ (aq) + 2e + Ca (s)
-2.868
Cl2 (9) + 2e - 2CI- (aq)
1.35827
Is there a maximum standard reduction
potential that the half-reaction used at
the cathode of this cl can have?
E = Ov
O yes, there is a maximum.
red
Co2+ (aq) + 2e- Co (s)
-0.28
Co3+ (aq) + e - Co2+ (aq)
1.92
If so, check the "yes" box and calculate
the maximum. Round your answer to 2
decimal places. If there is no upper
limit, check the "no" box.
O no maximum
Cr2+ (aq) + 2e - Cr (s)
-0.913
Cr3+ (aq) + 3e - Cr (s)
-0.744
Cr3+ (aq) + e - Cr2+ (aq)
-0.407
Cro42- (aq) + 4H20 (1) + 3e - Cr(OH)3 (s) + 50H" (aq)
-0.13
By using the information in the ALEKS
Data tab, write a balanced equation
describing a half reaction that could be
used at the cathode of this cell.
Cu2+ (aq) + 2e Cu (s)
0.3419
Cu2+ (ag) + e- - Cut (ag)
0.153
Note: write the half reaction as it would
Cu* (aq) + e - Cu (s)
0.521
actually occur at the cathode.
F2 (9) + 2e - 2F (ag)
- 2F (aq)
2.866
Fe2+ (ag) + 2e Fe (s)
--0.447
Fe3+ (aq) + e - Fe2+ (ag)
0.771
Explanation
Check
Fe3+ (aq) + 3e - Fe (s)
-0.037
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Transcribed Image Text:A certain half-reaction has a standard reduction potential E=+0.51 V. An engineer proposes using this half-reaction at the anode of a galvanic cell that must 'red provide at least 1.10 V of electrical power. The cell will operate under standard conditions. Note for advanced students: assume the engineer requires this half-reaction to happern lo Data Half-Reaction E° (V) Ag+ (aq) + e- Ag (s) 0.7996 Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have? = Ov Al3+ (aq) + 3e → Al (s) O yes, there is a minimum. %3D red -1.676 Au+ (aq) + e - Au (s) 1.692 If so, check the "yes" box and calculate the minimum. Round your answer to 2 decimal places. If there is no lower limit, check the "no" box. Au3+ (aq) + 3e Au (s) 1.498 O no minimum Ba2+ (aq) + 2e- + Ba (s) -2.912 Br2 (1) + 2e- - 2Br (aq) 1.066 Ca2+ (aq) + 2e + Ca (s) -2.868 Cl2 (9) + 2e - 2CI- (aq) 1.35827 Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cl can have? E = Ov O yes, there is a maximum. red Co2+ (aq) + 2e- Co (s) -0.28 Co3+ (aq) + e - Co2+ (aq) 1.92 If so, check the "yes" box and calculate the maximum. Round your answer to 2 decimal places. If there is no upper limit, check the "no" box. O no maximum Cr2+ (aq) + 2e - Cr (s) -0.913 Cr3+ (aq) + 3e - Cr (s) -0.744 Cr3+ (aq) + e - Cr2+ (aq) -0.407 Cro42- (aq) + 4H20 (1) + 3e - Cr(OH)3 (s) + 50H" (aq) -0.13 By using the information in the ALEKS Data tab, write a balanced equation describing a half reaction that could be used at the cathode of this cell. Cu2+ (aq) + 2e Cu (s) 0.3419 Cu2+ (ag) + e- - Cut (ag) 0.153 Note: write the half reaction as it would Cu* (aq) + e - Cu (s) 0.521 actually occur at the cathode. F2 (9) + 2e - 2F (ag) - 2F (aq) 2.866 Fe2+ (ag) + 2e Fe (s) --0.447 Fe3+ (aq) + e - Fe2+ (ag) 0.771 Explanation Check Fe3+ (aq) + 3e - Fe (s) -0.037 MacBook Air FII F12 DOD D00 F4 F10 20 esc F6 F7 F8 F9 F5 F1 F2 F3 @ #3 24 & * delete 2 4 6 8 9
ditions.
per olo Data
2H* (aq) + 2e- → H2 (g)
0.000
2H20 (1) + 2e- H2 (g) + 2OH (aq)
-0.8277
H202 (aq) + 2H* (aq) + 2e¯ → 2H20 (I)
1.776
I2 (s) + 2e - 21 (aq)
0.5355
2103 (aq) + 12H+ (aq) + 10e → I2 (s) + 6H20 (I)
1.195
Mg2+ (aq) + 2e Mg (s)
-2.372
Mn2+ (aq) + 2e¯ → Mn (s)
-1.185
MnO2 (s) + 4H* (aq) + 2e¯ → Mn2+ (aq) + 2H20 (I)
1.224
MnO4 (aq) + 8H+ (aq) + 5e- → Mn2+ (aq) + 4H2O (I)
1.507
Mn04 (aq) + 2H20 (1) + 3e → MnO2 (s) + 40H¯ (aq)
0.595
HNO2 (aq) + H+ (âq) + e¯ → NO (g) + H2O (1)
0.983
N2 (g) + 4H2O (1) + 4e¯ → 40H (aq) + N2H4 (aq)
-1.16
NO3 (aq) + 4H+ (aq) + 3e- → NO (g) + 2H20 (I)
0.957
Na+ (aq) + e - Na (s)
-2.71
Ni2+ (aq) + 2e - Ni (s)
-0.257
O2 (g) + 4H+ (aq) + 4e → 2H20 (1)
1.229
02 (g) + 2H2O (1) + 4e → 40H (aq)
0.401
O2 (g) + 2H+ (aq) + 2e H2O2 (aq)
0.695
Pb2+ (aq) + 2e → Pb (s)
-0.1262
PBSO4 (s) + H+ (aq) + 2e → Pb (s) + HSO4 (aq)
-0.3588
HSO4 (aq) + 3H+ (aq) + 2e H2SO3 (aq) + H20 (1)
0.172
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Transcribed Image Text:ditions. per olo Data 2H* (aq) + 2e- → H2 (g) 0.000 2H20 (1) + 2e- H2 (g) + 2OH (aq) -0.8277 H202 (aq) + 2H* (aq) + 2e¯ → 2H20 (I) 1.776 I2 (s) + 2e - 21 (aq) 0.5355 2103 (aq) + 12H+ (aq) + 10e → I2 (s) + 6H20 (I) 1.195 Mg2+ (aq) + 2e Mg (s) -2.372 Mn2+ (aq) + 2e¯ → Mn (s) -1.185 MnO2 (s) + 4H* (aq) + 2e¯ → Mn2+ (aq) + 2H20 (I) 1.224 MnO4 (aq) + 8H+ (aq) + 5e- → Mn2+ (aq) + 4H2O (I) 1.507 Mn04 (aq) + 2H20 (1) + 3e → MnO2 (s) + 40H¯ (aq) 0.595 HNO2 (aq) + H+ (âq) + e¯ → NO (g) + H2O (1) 0.983 N2 (g) + 4H2O (1) + 4e¯ → 40H (aq) + N2H4 (aq) -1.16 NO3 (aq) + 4H+ (aq) + 3e- → NO (g) + 2H20 (I) 0.957 Na+ (aq) + e - Na (s) -2.71 Ni2+ (aq) + 2e - Ni (s) -0.257 O2 (g) + 4H+ (aq) + 4e → 2H20 (1) 1.229 02 (g) + 2H2O (1) + 4e → 40H (aq) 0.401 O2 (g) + 2H+ (aq) + 2e H2O2 (aq) 0.695 Pb2+ (aq) + 2e → Pb (s) -0.1262 PBSO4 (s) + H+ (aq) + 2e → Pb (s) + HSO4 (aq) -0.3588 HSO4 (aq) + 3H+ (aq) + 2e H2SO3 (aq) + H20 (1) 0.172 acBook Air II F8 1) F7 F9 F10 F11 F12 * + 9. delete + II
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