a) For (AHvap n-hexane the vaporization enthalpy and entropy are given = 29.6 kJ mol 1; ASvap = 86.5 J mol-1 K-1). Calculate the boiling point when ambient conditions are used. b) Compare AHvap and ASvap. Which of the two values is nearly unchanged for many "normal" substances? Is there a behaviour or rule? Which compounds have an abnormal behaviour and why?

The molar enthalpy of vaporization of benzene at its normal boiling point (80.09° C) is 30.72 kJ mol. Assuming that Avap Hm and ApapSm stay constant at their values as 80.09•C, calculate the value of AvapGm at 75.0°C, 80.09°C, and 85.0°C. What do the values of -1 Avap Gm tell you about the spontaneity of the vaporization at these three temperatures?

Look up the boiling point of benzene. Then calculate the change in Gibbs Free Energy for the vaporization of benzene at temperatures both 10°C lower than its boiling point and 10°C higher than its boiling point. Then clearly discuss whether your calculations appear to be correct, and more importantly, why.

Consider the following reaction run at 25 °C: Ia (9) + Cla (g) = 2 ICI (g) a) A mixture at 25 °C containing 12 and C12 at a pressure of 0.125 atm and IC| at a pressure of 1.50 atm has DG=+1.41 kJ. Calculate the standard change in Gibbs free energy for this reaction and use the information to complete Part b) b) Fill in the blanks in the paragraph below. Write your answers in the boxes on your test template that correspond to the blanks in the paragraph. Under the specified conditions (P12 = Pca = 0.125 atm and Pıa = 1.50 atm) at 25 °C, the value AG = +1.41 kJ indicates that this reaction will proceed in the (i). direction until a state of (ii)_ is The standard free energy value, indicating that when Piz2 = the reached and the value of AG = (iii) change has a (iv). (v). reaction will proceed in the (viii). (ix). value of (x)_ - Pcla = (vi)_ , and Pici = (vii). direction until AG = At that point, the standard free energy change will have a at 298 K.