A force of 720 newtons stretches a spring 4 meters. A mass of 45 kilograms is attached to the end of the spring and is initially released from the equilibrium position wit an upward velocity of 6 m/s. Give the initial conditions. x(0) = x'(0) = m m/s Find the equation of motion. x(t) = m

University Physics Volume 1
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ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter15: Oscillations
Section: Chapter Questions
Problem 60AP: A mass is placed on a frictionless, horizontal table. A spring (k=100N/m) , which can be stretched...
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A force of 720 newtons stretches a spring 4 meters. A mass of 45 kilograms is attached to the end of the spring and is initially released from the equilibrium position with
an upward velocity of 6 m/s.
Give the initial conditions.
x(0) =
x'(0) =
m
3
m/s
Find the equation of motion.
x(t) =
Transcribed Image Text:A force of 720 newtons stretches a spring 4 meters. A mass of 45 kilograms is attached to the end of the spring and is initially released from the equilibrium position with an upward velocity of 6 m/s. Give the initial conditions. x(0) = x'(0) = m 3 m/s Find the equation of motion. x(t) =
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