A germanium diode is used to detect radiation with energy of 1.6 MeV. To do so, the anode (positive terminal) is exposed to the incoming radiation. Assume that the energy is absorbed entirely at the point of entry or the anode. With mobilities of 1,150 cm?/V.s for holes and 3,750 cm?/V.s for electrons, calculate the current through the diode with reverse bias: V = 24 V and d = 12 mm. Neglect the effects of electrodes and 4. of the n and p layers and assume a single radiation event, that is a single particle or a short burst of radiation. (Charge of an electron = 1.602 x 10-19 C; d is the distance between anode and cathode).

A germanium diode is used to detect radiation with energy of 1.6 MeV. To do so, the anode (positive terminal) is exposed to the incoming radiation. Assume that the energy is absorbed entirely at the point of entry or the anode. With mobilities of 1,150 cm?/V.s for holes and 3,750 cm?/V.s for electrons, calculate the current through the diode with reverse bias: V = 24 V and d = 12 mm. Neglect the effects of electrodes and 4. of the n and p layers and assume a single radiation event, that is a single particle or a short burst of radiation. (Charge of an electron = 1.602 x 10-19 C; d is the distance between anode and cathode).

Modern Physics

3rd Edition

ISBN:9781111794378

Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer

Publisher:Raymond A. Serway, Clement J. Moses, Curt A. Moyer

Chapter14: Nuclear Physics Applications

Section: Chapter Questions

Problem 15P

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