(a) Glycine is present predominantly as the species "HaN-CH2-COOH. (b) The average net charge of glycine is +1/2. c) Half of the amino groups are ionized. (d) The pH is equal to the pka of the carboxyl group. (e) The pH is equal to the pka of the protonated amino group. (f) Glycine has its maximum buffering capacity. (g) The average net charge of glycine is zero. (h) The carboxyl group has been completely titrated (first equivalence point). (i) Glycine is completely titrated (second equivalence point). G) The predominant species is *HaN-CH2-COO (k) The average net charge of glycine is 21. (1) Glycine is present predominantly as a 50:50 mixture of "H&N-CH2-COOH and "H3N-CH2-CO0 (m) This is the isoelectric point.

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter23: Polymeric Materials And Soft Condensed Matter
Section: Chapter Questions
Problem 30AP
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12
11.30
(V)
10
9.60
(IV)
pH
6---5.97
(III)
2.34.
2
KII)
0.5
1.0
1.5
2.0
OH- (equivalents)
(a) Glycine is present predominantly as the species HaN-CH2-COOH.
(b) The average net charge of glycine is +1/2.
(c) Half of the amino groups are ionized.
(d) The pH is equal to the pka of the carboxyl group.
(e) The pH is equal to the pka of the protonated amino group.
(f) Glycine has its maximum buffering capacity.
(g) The average net charge of glycine is zero.
(h) The carboxyl group has been completely titrated (first equivalence point).
(i) Glycine is completely titrated (second equivalence point).
(i) The predominant species is *HaN–CH2-COO
(k) The average net charge of glycine is 21.
(1) Glycine is present predominantly as a 50:50 mixture of *H3N-CH2-COOH and "H3N-CH2–COO
(m) This is the isoelectric point.
(n) This is the end of the titration.
(0) These are the worst pH regions for buffering power.
Transcribed Image Text:12 11.30 (V) 10 9.60 (IV) pH 6---5.97 (III) 2.34. 2 KII) 0.5 1.0 1.5 2.0 OH- (equivalents) (a) Glycine is present predominantly as the species HaN-CH2-COOH. (b) The average net charge of glycine is +1/2. (c) Half of the amino groups are ionized. (d) The pH is equal to the pka of the carboxyl group. (e) The pH is equal to the pka of the protonated amino group. (f) Glycine has its maximum buffering capacity. (g) The average net charge of glycine is zero. (h) The carboxyl group has been completely titrated (first equivalence point). (i) Glycine is completely titrated (second equivalence point). (i) The predominant species is *HaN–CH2-COO (k) The average net charge of glycine is 21. (1) Glycine is present predominantly as a 50:50 mixture of *H3N-CH2-COOH and "H3N-CH2–COO (m) This is the isoelectric point. (n) This is the end of the titration. (0) These are the worst pH regions for buffering power.
5. A 100 ml solution of 0.1 M glycine at pH 1.72 was titrated with 2 M NaOH solution. The pH was monitored,
and the results were plotted as shown in the graph. The key points in the titration are designated I to V. For
each of the statements (a) to (o), identify the appropriate key point in the titration.
12
11.30
10
9.60
(IV)
pH
6 ---5,97
(III)
4
2.34
2
KII)
Transcribed Image Text:5. A 100 ml solution of 0.1 M glycine at pH 1.72 was titrated with 2 M NaOH solution. The pH was monitored, and the results were plotted as shown in the graph. The key points in the titration are designated I to V. For each of the statements (a) to (o), identify the appropriate key point in the titration. 12 11.30 10 9.60 (IV) pH 6 ---5,97 (III) 4 2.34 2 KII)
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