A massless bar of length L = 4.0 m is placed on a pivot under its centre. A block of mass m1 4.4 kg is placed at a distance of ri 0.50 m to || the left of the pivot. A second block of mass m2 1.2 kg is placed at a distance of r2 1.5 m to the right of the pivot. (a) What is the net torque due to the masses m1 and m2? (b) Where must a third block of mass m3 = 1.1 kg be placed for the bar to be in static equilibrium? Note: static equilibrium means that the net torque is zero Take g = 9.81 m/s² and show all your work. L r2 mị m2

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Torque

Torque is the rotational equivalent of linear force in physics and mechanics. Based on the course of study, it is also known as the moment of force, rotational force, or turning effect.