A member is formed by connecting two steel bars shown below. Assuming that the bars are prevented from buckling sideways, calculate the magnitude force "P" that will cause the total length of the member to decrease 0.29 mm the values of elastic modulus for steel is 217 MPa. Take H1 = 4 cm, H2 = 11 cm, top bar (R) is 3 x 3 cm and bottom bar (Q) is 7 x 7 cm. Also, determine the stress-induced in each section of the bar. i) Magnitude Force, P = ii) Stress-induced in the top bar = iii) Stress-induced in the bottom bar =

A member is formed by connecting two steel bars shown below. Assuming that the bars are prevented from buckling sideways, calculate the magnitude force "P" that will cause the total length of the member to decrease 0.29 mm the values of elastic modulus for steel is 217 MPa. Take H1 = 4 cm, H2 = 11 cm, top bar (R) is 3 x 3 cm and bottom bar (Q) is 7 x 7 cm. Also, determine the stress-induced in each section of the bar. i) Magnitude Force, P = ii) Stress-induced in the top bar = iii) Stress-induced in the bottom bar =

Refrigeration and Air Conditioning Technology (MindTap Course List)

8th Edition

ISBN:9781305578296

Author:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson

Publisher:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson

Chapter1: Heat, Temperature, And Pressure

Section: Chapter Questions

Problem 17RQ: Convert 22C to Fahrenheit.

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A member is formed by connecting two steel bars shown below. Assuming that the bars are prevented from buckling sideways, calculate the magnitude force "P" that will cause the total length of the member to decrease 0.29 mm the values of elastic modulus for steel is 217 MPa. Take H₁ = 4 cm, H₂ = 11 cm, top bar (R) is 3 x 3 cm and bottom bar (Q) is 7 x 7 cm. Also, determine the stress-induced in each section of the bar.

i) Magnitude Force, P =

ii) Stress-induced in the top bar =

iii) Stress-induced in the bottom bar =

R cm x Rcm
Steel bar
H1 cm
Q cm x Q cm
Šteel bar
H2 cm

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