a rod of semiconducting meterial of length L = 3m and cross-sectioanal area A=2.5mm2 lies along the x axis between x=0 and x=L. the meterial obeys ohms law, and its resistivity varies along the rod according to p=p0(1-(x2/L2)) where p0=2.5 * 10-4 ohm*m. the end of the rod at x=0 is at a potential V0= 30 V greater than the end at x = L. a)what is the total resistance, in units of ohm, of the rod ?b)what is the current, in units of miliamperes in the rod?c)what is the electric potential, in units of Volt in the rod at x=L/2 ?d)what is the electric field magnitude E, in units of V/m, in the rod at x=L/2 ? () THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE.2.5 mm2 lies along the x-axis between r0 and r= L. The material obeys Ohm's law, and its resistivity varies along the rodA rod of semiconducting material of length L = 3 m and cross-sectional area Awhere Po = 2.5 x 10 S. m. The end of the rod at zL20 is at a potential Vo = 30 V greater than the end at zL.according to p = PoA) What is the total resistance, in units of N, of the rod?AnswerB) What is the current. in units of miliamperes in the rod?ofAnswer:stionC) What is the electric potential, in units of Volt in the rod at z= L/2?Answerut ofestion7D) What is the electric-field magnitude E, in units of V/m in the rod at = L/2?lout ofAnswerCuestion

The resistance of the material is R=ρLA…

Answered: a rod of semiconducting meterial of…

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter28: Current And Resistance

Section: Chapter Questions

Problem 68PQ

See similar textbooks

Related questions

Concept explainers

Question

a rod of semiconducting meterial of length L = 3m and cross-sectioanal area A=2.5mm2 lies along the x axis between x=0 and x=L. the meterial obeys ohms law, and its resistivity varies along the rod according to p=p0(1-(x2/L2)) where p0=2.5 * 10-4 ohm*m. the end of the rod at x=0 is at a potential V0= 30 V greater than the end at x = L.

a)what is the total resistance, in units of ohm, of the rod ?

b)what is the current, in units of miliamperes in the rod?

c)what is the electric potential, in units of Volt in the rod at x=L/2 ?

d)what is the electric field magnitude E, in units of V/m, in the rod at x=L/2 ?

() THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE.
2.5 mm2 lies along the x-axis between r
0 and r= L. The material obeys Ohm's law, and its resistivity varies along the rod
A rod of semiconducting material of length L = 3 m and cross-sectional area A
where Po = 2.5 x 10 S. m. The end of the rod at z
L2
0 is at a potential Vo = 30 V greater than the end at z
L.
according to p = Po
A) What is the total resistance, in units of N, of the rod?
Answer
B) What is the current. in units of miliamperes in the rod?
of
Answer:
stion
C) What is the electric potential, in units of Volt in the rod at z= L/2?
Answer
ut of
estion
7
D) What is the electric-field magnitude E, in units of V/m in the rod at = L/2?
lout of
Answer
Cuestion

Expert Solution

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions