A sample of a substance with the empirical formula XCI3 weighs 0.4884 g. When it is dissolved in water and all its chlorine is converted to insoluble AgCl by addition of an excess of silver nitrate, the mass of the resulting AgCl is found to be 1.2945 g. The chemical reaction is (a) Calculate the formula mass of XCI3. (b) Calculate the atomic mass of X. XCl3 + 3 AgNO3-3AgCl + X(NO3)3 Formula mass XCI3 = Atomic mass X = g mol-1 g mol-1

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Chapter2: Chemical Formulas, Equations, And Reaction Yields
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A sample of a substance with the empirical formula XCI3 weighs 0.4884 g. When it is dissolved in water and all its chlorine is
converted to insoluble AgCl by addition of an excess of silver nitrate, the mass of the resulting AgCl is found to be 1.2945 g. The
chemical reaction is
(a) Calculate the formula mass of XCI3.
(b) Calculate the atomic mass of X.
XCl3 + 3 AgNO3-3AgCl + X(NO3)3
Formula mass XCI3 =
Atomic mass X =
g mol-1
g mol-1
Transcribed Image Text:A sample of a substance with the empirical formula XCI3 weighs 0.4884 g. When it is dissolved in water and all its chlorine is converted to insoluble AgCl by addition of an excess of silver nitrate, the mass of the resulting AgCl is found to be 1.2945 g. The chemical reaction is (a) Calculate the formula mass of XCI3. (b) Calculate the atomic mass of X. XCl3 + 3 AgNO3-3AgCl + X(NO3)3 Formula mass XCI3 = Atomic mass X = g mol-1 g mol-1
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