A simple pendulum is set into motion at two different times with different initial conditions. The first time: the bob is in its equilibrium position and is given an initial velocity +2 m/s. The maximum height reached by the bob is h1,max and the period of motion is T1. The second time: the bob is in its equilibrium position and is given an initial velocity +6 m/s. The maximum height reached by the bob is h2,max and the period of motion is T2. Assume that the motion is simple harmonic, which of the following is true? h2.max=9h,max and T, = T, 9hmax and T2 T1 hzmax= 4h max and T, = 7, %3D Then we have: O Then we have: h2.max 4h,max and T, = 27, 4h hz max 9h max and T = 3T, %3D %3D %3D %3D Then we have: O Then we have

Principles of Physics: A Calculus-Based Text
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Chapter7: Conservation Of Energy
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A simple pendulum is set into motion at two different times with different initial
conditions. The first time: the bob is in its equilibrium position and is given an
initial velocity +2 m/s. The maximum height reached by the bob is h1,max and the
period of motion is T1. The second time: the bob is in its equilibrium position and
is given an initial velocity +6 m/s. The maximum height reached by the bob is
h2,max and the period of motion is T2. Assume that the motion is simple.
harmonic, which of the following is true?
hz.max = 9h, max and T, = T,
%3D
hamax = 42, nax end T,-7,
Then we have:
Then we have:
h2.max 4h,max and T, = 27,
hzmax = 9h1max and T 3T,
Then we have:
Then we have
Transcribed Image Text:A simple pendulum is set into motion at two different times with different initial conditions. The first time: the bob is in its equilibrium position and is given an initial velocity +2 m/s. The maximum height reached by the bob is h1,max and the period of motion is T1. The second time: the bob is in its equilibrium position and is given an initial velocity +6 m/s. The maximum height reached by the bob is h2,max and the period of motion is T2. Assume that the motion is simple. harmonic, which of the following is true? hz.max = 9h, max and T, = T, %3D hamax = 42, nax end T,-7, Then we have: Then we have: h2.max 4h,max and T, = 27, hzmax = 9h1max and T 3T, Then we have: Then we have
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