A simple pendulum is set into motion at two different times with different initial conditions. The first time: the bob is in its equilibrium position and is given an initial velocity +4 m/s. The maximum height reached by the bob is h1,max and the period of motion is T1. The second time: the bob is in its equilibrium position and is given an initial velocity +2 m/s. The maximum height reached by the bob is h2,max and the period of motion is T2. Assume that the motion is simple harmonic, which of the following is true? h2.max = 9hmax and T, = 37, %3D hz.max = 4h1,max and T2 = T1 %3D O Then we have : O Then we have: h2,max = h1max/4 and T = T, %3D h2max = 4h, max and T = 2T, %3D

Physics for Scientists and Engineers: Foundations and Connections
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Chapter16: Oscillations
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A simple pendulum is set into motion at two different times with different initial
conditions. The first time: the bob is in its equilibrium position and is given an
initial velocity +4 m/s. The maximum height reached by the bob is h1,max and the
period of motion is T1. The second time: the bob is in its equilibrium position and
is given an initial velocity +2 m/s. The maximum height reached by the bob is
h2,max and the period of motion is T2. Assume that the motion is simple
harmonic, which of the following is true?
h2,max = 9hpax and T = 37,
h2.max = 4h1,max and T2 = T,
Then we have :
O Then we have:
h2,max = h1,max/4 and T = T,
h2max = 4h1max and T, = 2T,
уре
TECNO
OƆ TAIVES CAMON
Transcribed Image Text:O3 sec A simple pendulum is set into motion at two different times with different initial conditions. The first time: the bob is in its equilibrium position and is given an initial velocity +4 m/s. The maximum height reached by the bob is h1,max and the period of motion is T1. The second time: the bob is in its equilibrium position and is given an initial velocity +2 m/s. The maximum height reached by the bob is h2,max and the period of motion is T2. Assume that the motion is simple harmonic, which of the following is true? h2,max = 9hpax and T = 37, h2.max = 4h1,max and T2 = T, Then we have : O Then we have: h2,max = h1,max/4 and T = T, h2max = 4h1max and T, = 2T, уре TECNO OƆ TAIVES CAMON
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