A solid circular rod that is 600 mm long and 20 mm in diameter is subjected to an axial force of P = 50 kN. The elongation of the rod is 8 = 1.40 mm, and its diameter becomes d2 = 19.9837 mm. Assume that the material does not yield. Determine the following: P = 50 kN 600 mm 20 mm P = 50 kN The normal stress is equal to in MPa: The normal Strain is equal to: The modulus of elasticity is equal to in GPa: The changes in diameter (Ad) is equal to in mm: The passion ratio is equal to: The shear modulus is equal to in GPa:

A solid circular rod that is 600 mm long and 20 mm in diameter is subjected to an axial force of P = 50 kN. The elongation of the rod is 8 = 1.40 mm, and its diameter becomes d2 = 19.9837 mm. Assume that the material does not yield. Determine the following: P = 50 kN 600 mm 20 mm P = 50 kN The normal stress is equal to in MPa: The normal Strain is equal to: The modulus of elasticity is equal to in GPa: The changes in diameter (Ad) is equal to in mm: The passion ratio is equal to: The shear modulus is equal to in GPa:

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter7: Analysis Of Stress And Strain

Section: Chapter Questions

Problem 7.6.13P: A solid spherical ball of magnesium alloy (E = 6.5 × l0-6 psi, v = 0.35) is lowered into the ocean...

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