A solution is prepared such that the initial concentration of Cd2+ is 3.80×10-2 M and the initial concentration of Br is 7.50x10-2 M. Cd2+ and Br are allowed to react as shown below to establish equilibrium with the complex CdBr42-. equilibrium concentration of the complex CdBr42- is determined to be 2.9×10-3 M. Cd2* (aq) + 4 Br (aq) = CdBr42- (aq) %3D What is the formation constant, Kf, for this complex?

Chemistry by OpenStax (2015-05-04)
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Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
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Chapter15: Equilibria Of Other Reaction Classes
Section: Chapter Questions
Problem 17E: Assuming that no equilibria other than dissolution are involved, calculate the concentration of all...
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QUESTION 1
A solution is prepared such that the initial concentration of Cd2+ is 3.80x10-2 M and the initial concentration of Br" is
7.50x10-2 M. Cd2+ and Br are allowed to react as shown below to establish equilibrium with the complex CdBr42.The
equilibrium concentration of the complex CdBr42- is determined to be 2.9x10-3 M.
Cd2+ (aq) + 4 Br (aq) = CdBr42- (aq)
%3D
What is the formation constant, Kf, for this complex?
Transcribed Image Text:QUESTION 1 A solution is prepared such that the initial concentration of Cd2+ is 3.80x10-2 M and the initial concentration of Br" is 7.50x10-2 M. Cd2+ and Br are allowed to react as shown below to establish equilibrium with the complex CdBr42.The equilibrium concentration of the complex CdBr42- is determined to be 2.9x10-3 M. Cd2+ (aq) + 4 Br (aq) = CdBr42- (aq) %3D What is the formation constant, Kf, for this complex?
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