A solution of Nacl was prepared by dissolving 0.8766 g solid NaCl in 100 ml. Then 10.0 ml from this solution was titratel with 15.55 ml of AgNO3 using chromate indicator, calculate the concentration of AGNO3 in (mol/L) 1. 0.733 mol/L 2. o0965 mol/L. 3. d.965 mol/L 0.150 mol/L None of the above 4. 5.

A solution of Nacl was prepared by dissolving 0.8766 g solid NaCl in 100 ml. Then 10.0 ml from this solution was titratel with 15.55 ml of AgNO3 using chromate indicator, calculate the concentration of AGNO3 in (mol/L) 1. 0.733 mol/L 2. o0965 mol/L. 3. d.965 mol/L 0.150 mol/L None of the above 4. 5.

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter13: Titrations In Analytical Chemistry

Section: Chapter Questions

Problem 13.30QAP

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Normality is same as Molarity for sodium hydroxide and normal = molar (for NaOH) Normality of sodium hydroxide = 0.10395N (normal) or Molarity of NaOH = 0.10395M (molar) Volume of NaOH consumed during the titration = 21.87 mL Mol wt of Naproxen = 230.26 g/mol Weight of Naproxen ds (i.e., sample) = 0.534g Calculate the % Purity (dried-basis) of Naproxen ds, given that the LOD results for Naproxen = 1.0% a 97.0 b 98.0 c 98.5 d 99.0 e 99.5 f none of the other answers.
A mixture containing KCl and NaBr was analyzed by Mohr's method. A mass of 0.31011 g of the mixture was dissolved in 50 mL of water, the Na2CrO4 indicator was added, and it was titrated with a 0.11011 mol/L AgNO3 solution. The endpoint was 36.011 mL. What are the % m/m concentrations of KCl and NaBr in the mixture?
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Express the concentration of acetic acid in both samples as % by mass of acetic per 100mL of solution given : %= mass/ volumex100% Given: NaOH vs CH3COOH Burette solution is NaOH and the pipette solution is 5.0 mL of Vinegar Titration Initial burette reading Final burette reading Volume of NaOH consumed Average volume of NaOH Approximate 0.0 mL 20.1 mL 20.1 mL 20.3 mL Titration 1 0.0 mL 20.9 mL 20.9 mL Titration 2 0.0 mL 20.0 mL 20.0 mL To find the average volume Average volume = 20.1 mL + 20.9 mL + 20.0 mL320.1 mL + 20.9 mL + 20.0 mL3 = 20.3 mL Concentration of Vinegar = Volume of NaOH * Concentration of NaOHVolume of vinegarVolume of NaOH * Concentration of NaOHVolume of vinegar = 20.3 mL * 0.0647 M5.0 mL20.3 mL * 0.0647 M5.0 mL = 0.2627 M Concentration of NaOH = Volume of H2SO4 * Concentration of H2SO4Volume of NaOHVolume of H2SO4 * Concentration of…
0.890 g KIO3 was dissolved to give a 80.00 mL Iodate solution. 35.00 mL aliquot reactedwith the iodide to form triiodide. The liberated triiodide was titrated and consumed 11.65 mL of theS2O32- solution to reach endpoint. Calculate the concentration in molarity of the Na2S2O3solution.
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A 5.50 mL sample of an H3PO4H3PO4 solution of unknown concentration is titrated with a 1.050×10−2 MNaOH solution. A volume of 7.32 mL of the NaOH solution was required to reach the equivalence point. What is the concentration of the unknown H3PO4H3PO4 solution? Express your answer with the appropriate units. value/units
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