letter B only A solution was prepared by dissolving 1310 mg of K3 Fe (CN). (329 2 g/mol) in sufficient water to give 720 mL. Calculatea the molar analytical concentration of K3 Fe (CN), -Molar analytical concentration = 0.0055Mthe molar concentration ofK*Molar concentration = 0.0165M%3Dthe molar concentration of Fe (CN),Molar concentration 0.0055MCorrectb the weight/volume percentage of K3 Fe (CN), -Weight/volume percentage =% (w/v)the number of millimoles of K* in 48.0 mL of this solution.mmol3-ppm Fe (CN),PreviousNeppmacer

Note : I have been asked to solve part B only.

A solution was prepared by dissolving 1310 mg of K3 Fe (CN), (329.2 g/mol) in sufficient water to give 720 mL. Calculate a the molar analytical concentration of K3 Fe (CN),- Molar analytical concentration = 0.0055 M the molar concentration of K+. Molar concentration = 0.0165 M the molar concentration of Fe (CN),. Molar concentration = 0.0055 M Correct b the weight/volume percentage of K3 Fe (CN),. Weight/volume percentage = % (w/v) the number of millimoles of K in 48.0 mL of this solution. mmol 3- ppm Fe (CN), ppm acer

A solution was prepared by dissolving 1310 mg of K3 Fe (CN), (329.2 g/mol) in sufficient water to give 720 mL. Calculate a the molar analytical concentration of K3 Fe (CN),- Molar analytical concentration = 0.0055 M the molar concentration of K+. Molar concentration = 0.0165 M the molar concentration of Fe (CN),. Molar concentration = 0.0055 M Correct b the weight/volume percentage of K3 Fe (CN),. Weight/volume percentage = % (w/v) the number of millimoles of K in 48.0 mL of this solution. mmol 3- ppm Fe (CN), ppm acer

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter13: Titrations In Analytical Chemistry

Section: Chapter Questions

Problem 13.29QAP

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