e on a Small Scale83tory Questionsswers and additional paper if necessary.)3. Precipitate formation provides one means for re-covering precious metal tons from waste water. For ex-ample, silver ion (Ag*) can be recovered by precipita-tion as silver chloride (AgCl). The net ionic equationfor this reaction is shown in Equation 7.Ag*(aq) + Cr"(aq) → AgCl(s)(Eq. 7)(1) What volume, in milliliters, of 8.75 x 10-2Msodium chloride solution (NaCI) would be required tocompletely precipitate the Ag* ion from one liter ofwaste water that is 9.00 x 10M in Ag* lon?(2) Calculate the theoretical yield, in grams, ofthis procedure.(3) What mass of AgCl would be collected if thepercent yield of this precipitation were 85%?

We hsve to find the volume of NaCl to precipitate AgCl and calculate its theoretical yield

Precipitate vering precious metal tons from waste water. For ex- ple, silver ion (Ag*) can be recovered by precipita- n as silver chloride (AgCl). The net ionic equation this reaction is shown in Equation 7. Ag*(aq) + cr(aq) → AgCI(s) (Eq. 7) (1) What volume, in milliliters, of 8.75 x 10-2M ium chloride solution (NaCl) would be required to mpletely precipitate the Ag* ion from one liter of te water that is 9.00 x 10 M in Ag* lon?

Precipitate vering precious metal tons from waste water. For ex- ple, silver ion (Ag) can be recovered by precipita- n as silver chloride (AgCl). The net ionic equation this reaction is shown in Equation 7. Ag(aq) + cr(aq) → AgCI(s) (Eq. 7) (1) What volume, in milliliters, of 8.75 x 10-2M ium chloride solution (NaCl) would be required to mpletely precipitate the Ag* ion from one liter of te water that is 9.00 x 10 M in Ag* lon?

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter15: Acid–base Equilibria

Section: Chapter Questions

Problem 98AP

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