A student ran the following reaction in the laboratory at 333 K: CHĄ(g) + CC14(g) 2CH,C,(g) When he introduced CH4(g) and CC1,(g) into a 1.00 L evacuated container, so that the initial partial pressure of CH4 was 0.694 atm and the initial partial pressure of CCl, was 0.279 atm, he found that the equilibrium partial pressure of CH,Cl, was 0.100 atm. Calculate the equilibrium constant, Kp, he obtained for this reaction. Кр Kp =

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Chapter12: Chemical Equilibrium
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A student ran the following reaction in the laboratory at 333 K:
CHĄ(g) + CC14(g) 2CH,C,(g)
When he introduced CH4(g) and CC1,(g) into a 1.00 L evacuated container, so that
the initial partial pressure of CH4 was 0.694 atm and the initial partial pressure of
CCl, was 0.279 atm, he found that the equilibrium partial pressure of CH,Cl, was
0.100 atm.
Calculate the equilibrium constant, Kp, he obtained for this reaction.
Кр
Kp =
Transcribed Image Text:A student ran the following reaction in the laboratory at 333 K: CHĄ(g) + CC14(g) 2CH,C,(g) When he introduced CH4(g) and CC1,(g) into a 1.00 L evacuated container, so that the initial partial pressure of CH4 was 0.694 atm and the initial partial pressure of CCl, was 0.279 atm, he found that the equilibrium partial pressure of CH,Cl, was 0.100 atm. Calculate the equilibrium constant, Kp, he obtained for this reaction. Кр Kp =
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