a) The following information is given for a 34.5 kW, 23 shunt field, series field, diverter and armature resistance including brush resistance are 920, 0.0150, 0.030, 0.0320 respectively. Determine the distribution of the generated power.
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- A 10kW 220 volt compound generator is operated at no load at theproper armature voltage and speed, from which the stray power losscalculations are determined to be 705 watts. The shunt field resistance is110 ohms, the armature resistance is 0.265 ohm, and the series fieldresistance is 0.035 ohm. Assume a 2 volt brush drop and (a) calculate thefull load efficiency. (b) Calculate also the maximum efficiency.Problem: A short-shunt compound generator has armature, shunt field and series field resistances of 0.5 Ω, 156 Ω, and 0.465 Ω respectively. If it supplies a load of 9 kW at a terminal voltage of 241 V, calculate the generated emf in volt. *Four decimal placesA 25kW, 250V DC shunt generator has armature and field resistances of 0.06 ohm and 100 ohm respectively. Determine the total armature power developed when working (i) as a generator delivering 25kW output and (ii) as a motor taking 25kW.
- the armature series field and shunt field resistance of a 125 kw, 250V long shunt cumulative compound DC generator are 0.025ohms, 0.01ohms and 30 ohms, respectively. If the stray power stray loss at rated load is 25 kW, determine the power in the shunt field. Assume a astray load loss of 1% of the load power output (note: Input power generator is equal to the motor brake horsepower, Pin=Pl+Plosses) Choices A. 2034.5 W B.2082.5 W C. 2065.5 W D. 2053.5 WAn A 20kW DC shunt generator having an armature circuit resistance of 0.8Ω and a field resistance of 140 Ω, generates a terminal voltage of 230V at full load. Determine the total iron, friction and windage losses if the efficiency of the generator at full load= 83%.Draw DC. Shunt generator which gives a full load output (30 K Watt) at the main voltage source of 200 voltage. In addition, gives the armature and shunt field resistors (0.05Ω and 50Ω), having 1000 watt iron and fractional losses. Calculate the Electro Magnetic field (EMF), Efficiency and Copper Loss.
- A long-shunt compound generator delivers a load current of 50A at 500V and has armature, series field and shunt field resistances of 0.05 ohms, 0.03 ohms and 250 ohms respectively. Calculate the generated voltage and the armature current. Allow 1V per brush for contact drop.A short shunt compound generator supplies a load of 10 kW at 200 V through a pair of feeder and series field resistance 0.10 ohm. Armature resistance, shunt field resistance and series field resistance are 0.01 ohm, 52.2 ohms and 0.10 ohm, respectively. If the core friction and windage losses amount to 631 watts, the BHP of the driving engine is nearest toQ1 / Answer the following questions 1 - what are the basic essential parts of an electrical generator? 2- What is the function of armature core in generator? 3- What is the meaning of standing losses? 4- What are the reasons for using three phase system to generat and distribute electrical power.
- A long-shunt compound generator delivers a load current of 50 A at 400 V and has armature, series field and shunt field resistances of 0.05 Ω, 0.03 Ω and 225 Ω respectively. Calculate the generated voltage and the armature current. Allow 1 V per brush for contact drop.Find the parameters of this 25 kW Generator with Armature Current of 30AQ2:- a long-shunt compound generator, the terminal voltage is 220 V when generator delivers 140 A. Find (a) e.m.f. (b) total power In the generated and (c) power of each Resistance . Given that shunt field, series field, diverter and armature resistance are 120 Q, 0.022 Q, 0.045 Q and 0.032 Q respectively.