A thermodynamic study of DyCl; determined its standard enthalpy of formation from the following information (1) DyCl;(s) — DуСl;(aq, in 4.0 M нсI) (2) Dy(s) + 3HCІ(аg, 4.0 M) — DyClз(аq, in 4.0 M нCI) +(o) дня 3—180.06 КkJ/mol дне 3— 699.43 k]/mol дне 3— 158.31 k]/mol (3) Н,(9) + {cl,o) — нсцад,4.0 М) Determine дн? (DyуClз,5) from these data.

Chemistry: Principles and Practice
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Chapter5: Thermochemistry
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A thermodynamic study of DyCl; determined its standard enthalpy of formation from the
following information
(1) DyCl3(s) → DyCl3(aq, in 4.0 M HCI)
(2) Dy (s) + 3нсі(аq, 4.0 M) — DyClз(аq, in 4.0 M нсІ) +н, (9)
дня — — 180.06 kJ /mol
дня — —699.43 k]/mol
дне 3 — 158.31 k]/mol
= -
(3) H, (g) +Cl2(g) → HCI(aq, 4.0 M)
Determine AH? (DyCl3, s) from these data.
Transcribed Image Text:A thermodynamic study of DyCl; determined its standard enthalpy of formation from the following information (1) DyCl3(s) → DyCl3(aq, in 4.0 M HCI) (2) Dy (s) + 3нсі(аq, 4.0 M) — DyClз(аq, in 4.0 M нсІ) +н, (9) дня — — 180.06 kJ /mol дня — —699.43 k]/mol дне 3 — 158.31 k]/mol = - (3) H, (g) +Cl2(g) → HCI(aq, 4.0 M) Determine AH? (DyCl3, s) from these data.
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