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A three-step process for producing molten iron metal from Fe2O3 is:3Fe2O3 + CO → 2Fe3O4 + CO2Fe3O4 + CO → 3FeO + CO2FeO + CO → Fe + CO2Assuming that the reactant CO is present in excess and that the yields, respectively, for the three steps are 96.3%, 58.9% and 82.6%, what mass of iron metal would be produced from 410. kg of Fe2O3?

Question

A three-step process for producing molten iron metal from Fe2O3 is:

  1. 3Fe2O3 + CO → 2Fe3O4 + CO2
  2. Fe3O4 + CO → 3FeO + CO2
  3. FeO + CO → Fe + CO2

Assuming that the reactant CO is present in excess and that the yields, respectively, for the three steps are 96.3%, 58.9% and 82.6%, what mass of iron metal would be produced from 410. kg of Fe2O3?

check_circleAnswer
Step 1

Given,

The three-step process for producing molten iron metal from Fe2O3 is:

  1. 3 Fe2O3 + CO → 2 Fe3O4 + CO2
  2. Fe3O4 + CO → 3 FeO + CO2
  3. FeO + CO → Fe + CO2

Since CO2 is gas, so the yields are given for iron compounds only.

% yield of Fe3O4 = 96.3 %

% yield of FeO = 58.9 %

% yield of Fe = 82.6 %

Mass of Fe2O3 = 410 kg = 410000 g

Moles of Fe2O3 can be calculated as:

Molar mass of Fe O3 (2x55.8)
(3x16)= 159.6 g/mol
Mass
410000 g
Moles
= 2568.92 mol
Molar mass
159.6 g/mol
help_outline

Image Transcriptionclose

Molar mass of Fe O3 (2x55.8) (3x16)= 159.6 g/mol Mass 410000 g Moles = 2568.92 mol Molar mass 159.6 g/mol

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Step 2

In step 1, amount of Fe3O4 produced from Fe2O3 can be calculated as:

3 mol of Fe2O3 produces-
2 mol of Fe304
2 mol
. 2568.92 mol of Fe2O3 produces-
x 2568.92 mol
3 mol
= 1712.61 mol of Fe3O4
help_outline

Image Transcriptionclose

3 mol of Fe2O3 produces- 2 mol of Fe304 2 mol . 2568.92 mol of Fe2O3 produces- x 2568.92 mol 3 mol = 1712.61 mol of Fe3O4

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Step 3

Actual yield of Fe3O4 can be cal...

Actual yield
Theoritical yield
% yield of Fe3O4
x 100%
% yield x Theoritical yield
Actual yield of Fe3O4'
100%
96.3 %X 1712.61 mol
Actual yield of Fe3O4
= 1649.24 mol
100%
help_outline

Image Transcriptionclose

Actual yield Theoritical yield % yield of Fe3O4 x 100% % yield x Theoritical yield Actual yield of Fe3O4' 100% 96.3 %X 1712.61 mol Actual yield of Fe3O4 = 1649.24 mol 100%

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