A triangle has sides of length 10cm and 12cm and has an area of 50 sq cm. a) Find the possible approximate values of the third length of the triangle (HINT: A = Vs(s – a)(s – b)(s – c) where a, b, and c are the lengths of the sides and s is the semiperimeter of the triangle) b) For each possible triangle, use the Law of Cosines to find the angle (ap- proximate value, in degrees) between the given sides. (NOTE that to find the angle, the Law of Cosines can be written as a² + b² – c² - C = cos 2ab

A triangle has sides of length 10cm and 12cm and has an area of 50 sq cm. a) Find the possible approximate values of the third length of the triangle (HINT: A = Vs(s – a)(s – b)(s – c) where a, b, and c are the lengths of the sides and s is the semiperimeter of the triangle) b) For each possible triangle, use the Law of Cosines to find the angle (ap- proximate value, in degrees) between the given sides. (NOTE that to find the angle, the Law of Cosines can be written as a² + b² – c² - C = cos 2ab

Elementary Geometry For College Students, 7e

7th Edition

ISBN:9781337614085

Author:Alexander, Daniel C.; Koeberlein, Geralyn M.

Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.

Chapter6: Circles

Section6.3: Line And Segment Relationships In The Circle

Problem 39E: The center of a circle of radius 2 in. is at a distance of 10 in. from the center of a circle of...

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