A two-liter sample of mineral water was evaporated to a small volume, following which the potassium fon was precipitated with excess sodium tetraphenylboron: K NaB(CHs)a → KB(CHs)4 nv The precipitate was filtered, washed and redissolved in acetone. The analysis was completed by a Mohr titration that required 43.85-mL of 0.03941M AGNO,: KB(C,Hs)4 9 + Ag → AgB(CHs)4 09 + K* Calculate the potassium ion concentration (parts per million) of the water sample. Molar Mass: K = 39.10

Fundamentals Of Analytical Chemistry
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Author:Skoog
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Chapter17: Complexation And Precipitation Reactions And Titrations
Section: Chapter Questions
Problem 17.35QAP
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Answer provided: 33.8-ppm K^+1
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answer clearly and readable. Thank you.
Transcribed Image Text:Answer provided: 33.8-ppm K^+1 Please show your complete solution and write your answer clearly and readable. Thank you.
A two-liter sample of mineral water was evaporated to a small volume, following which the potassium
ion was precipitated with excess sodium tetraphenylboron:
K+ NaB(C,Hs)4 → KB(CHs)4 )
The precipitate was filtered, washed and redissolved in acetone. The analysis was completed by a
Mohr titration that required 43.85-mL of 0.03941M AGNO3:
KB(C,Hs)4 19 + Ag → AgB(CHs)« co) + K**
Calculate the potassium ion concentration (parts per million) of the water sample.
Molar Mass:
K = 39.10
Transcribed Image Text:A two-liter sample of mineral water was evaporated to a small volume, following which the potassium ion was precipitated with excess sodium tetraphenylboron: K+ NaB(C,Hs)4 → KB(CHs)4 ) The precipitate was filtered, washed and redissolved in acetone. The analysis was completed by a Mohr titration that required 43.85-mL of 0.03941M AGNO3: KB(C,Hs)4 19 + Ag → AgB(CHs)« co) + K** Calculate the potassium ion concentration (parts per million) of the water sample. Molar Mass: K = 39.10
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