A voltaic cell is set up at 25 °C and delivers 0.060 V. One half cell contains an acidified solutic of permanganate and manganese(IlI) ions, and the other half-cell is based on the followir 3.2 reaction: Br05 (aq) + 6H30*(aq) + 6e¯ → Br (aq) + 9H20 (8), Eed = 1.44 V %3D 3.2.1 Write down the fully balanced cell-reaction equation.

Chemistry: The Molecular Science
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Chapter17: Electrochemistry And Its Applications
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Q3.2
A voltaic cell is set up at 25 °C and delivers 0.060 V. One half cell contains an acidified solution
permanganate and manganese(II) ions, and the other half-cell is based on the following
reaction:
3.2
of
Br05 (aq) + 6H30+(aq) + 6e¯ → Br¯(aq) + 9H20 (£), Eed = 1.44 V
%3D
3.2.1 Write down the fully balanced cell-reaction equation.
[Mn²+]6
[MnO7]6
3.2.2
What must the value of the ratio
be if [BrO5] = 0.90 M, [Br¯] =1.11 M, and the
pH = 0.60?
Transcribed Image Text:A voltaic cell is set up at 25 °C and delivers 0.060 V. One half cell contains an acidified solution permanganate and manganese(II) ions, and the other half-cell is based on the following reaction: 3.2 of Br05 (aq) + 6H30+(aq) + 6e¯ → Br¯(aq) + 9H20 (£), Eed = 1.44 V %3D 3.2.1 Write down the fully balanced cell-reaction equation. [Mn²+]6 [MnO7]6 3.2.2 What must the value of the ratio be if [BrO5] = 0.90 M, [Br¯] =1.11 M, and the pH = 0.60?
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