A. A student performed the following reaction, and took an IR spectrum of the product. Do you think his/her reaction was successful? Briefly explain. , OH Na2Cr207 INFRARED SPECTRUM 0.8- 0.6 0.4 0.2 3000 2000 1000 Wavenumber (cm-1) Transmitance
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- Why KBr used in IR spectroscopic sample preparation? Please shortly answer at your own words. Answer should be to the point (Specific 2-3 lines).The data is for the molecular formula C8H8O3 (vanillin) with a mass of 152. Analyze the Mass spec data (include a table listing the molecular ion, base peak, and any other relevant fragments) – also include structures of fragments.Suggest and describe a less destructive MS technique and sketch the corresponding MS spectrum. Explain differences between the given MS spectrum below with the predicted spectrum.
- look at the reaction (first image) we can safely say that the signal that 2.22 ppm is hydrogen atom of a alcohol functional group. - Explain why does its signal appears in the 1H NMR spectrum as singlet? - Its coupling constant is zero or similar is not fully acceptable as answer.I am talking about this one on the ir spectroscopy we have carbon carbon double bond on benzen the three double bond so if we have that cant we say we have to csp2-H on the graph around 3100cm-1 thank uFully annotate ms. Using specific pieces of data from the spectra please discuss how you determined the identity of the terpene unknown. Your answer should be 1-2 paragraphs.
- Please fully annotate this IR spectrum in the picture below, no need to annotate the fingerprint region (400-1500 cm-1). Thank you so much!!Draw the instrumentation of ATR spectroscopy? Please answer at your own words.Record your absorbance data for the YELLOW and RED dyes below. Calculate the dye concentration in mM for each cuvette using M1V2 = M2v2 . Remember the concentration of stock solutions (100^ % dye) is 0.020 mM(mM= millimolar =mm /L). Data for YELLOW: peak absorbance used on spectrophotometer =420nm Cuvette 1 - 100% dye = 0.680 absorption Cuvette 2 - 75% dye = 0.510 absorption Cuvette 3 - 50% dye = 0.340 absorption Cuvette 4 - 25% dye = 0.170 absorption Data for RED - peak absorption used on spectrophotometer = 500nm Cuvette 1 - 100% dye: 0.621 absorption Cuvette 2 - 75%: 0.466 absorption Cuvette 3 - 50% dye: 0.311 absorption Cuvette 4 - 25% dye: 0.1555 absorption
- 1HNMR spectrum from the literature table labeled diagram chemical shift (literature), multiplet structure, integration, assignment please all in table based on the data in the lab FOR EXAMPLE NO Chemical shift experimental multiplet Integration Assignment 1 7.45 ppm Triplet 1 Para to Cl 2 7.55 ppm Triplet 1 Meta to Cl 3 7.56 ppm Doublet 1 Ortho to Cl 4 7.81 ppm Doublet 1 Ortho to Cl 5 13.43 ppm Singlet 1 -COOHhello i submitted this steady state approximation question but the answer you provided was very confusing. can you please show me handwritten steps as to how you got each answer instead of typed out answers. it would be greatly appreciated! I attached the image of the questionWhy are solid forms of the sample are not suitable for Uv-visible spectroscopy and Fluorescence spectroscopy? Please shortly answer at your own words. Answer should be specific (3-4 lines).