k₁[A] [B] k2k3 [A] [D] 2k1k3[A]²[B] k2[D] 2k₁[A][B] k₁[A] [B] k3 [A] k₁[A][B]-k₂[C][D]-k3[A][C] k₁[A] [B] k2[D]+k3[A] 2k1k3 [A]²[B] k2[D]+k3[A] None of the above < =[C] d[C] dt d[D] dt 11 22 = (when k3 << k₁ ~ kq) (in all instances) d[A] dt d[D] ~dt (when k3 >> k₁k₂)

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter13: Chemical Kinetics
Section: Chapter Questions
Problem 13.20QE
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hello i submitted this steady state approximation question but the answer you provided was very confusing. can you please show me handwritten steps as to how you got each answer instead of typed out answers. it would be greatly appreciated! 

I attached the image of the question

Match the expressions to complete the equations, making use of the Steady State Approximation.
k₁ [A][B]
A k2k3[A][D]
2k1k3[A]²[B]
k2[D]
c 2k₁ [A][B]
B
D
k₁[A][B]
k3 [A]
E k₁[A][B]-k₂[C][D]-k3[A][C]
k₁[A] [B]
F k2[D]+k3[A]
2k1k3[A]²[B]
k2[D]+k3[A]
H None of the above
G
Ev
F v
B V
Dv
=[C]
d[C]
dt
||
22
22
d[D]
dt
(when k3 << k₁ ~ k ₂)
(in all instances)
(when k3 >> k₁ ~k ₂)
d[A]
dt
dt
Transcribed Image Text:Match the expressions to complete the equations, making use of the Steady State Approximation. k₁ [A][B] A k2k3[A][D] 2k1k3[A]²[B] k2[D] c 2k₁ [A][B] B D k₁[A][B] k3 [A] E k₁[A][B]-k₂[C][D]-k3[A][C] k₁[A] [B] F k2[D]+k3[A] 2k1k3[A]²[B] k2[D]+k3[A] H None of the above G Ev F v B V Dv =[C] d[C] dt || 22 22 d[D] dt (when k3 << k₁ ~ k ₂) (in all instances) (when k3 >> k₁ ~k ₂) d[A] dt dt
Consider the following generic two-step reaction mechanism.
k₁
Step 1:
A + B
Step 2: A + C
k₂
k3
-
C + D
B + D
Transcribed Image Text:Consider the following generic two-step reaction mechanism. k₁ Step 1: A + B Step 2: A + C k₂ k3 - C + D B + D
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