25 One hundred grams of a dye compound isequivalent to 0.1871 moles. Its percentcomposition is shown below:PercentElementAtomic MassComposition35.95%12.011 amuH1.69%1.008 amuN10.49%14.007 amuNa12.92%22.990 amu26.97%15.999 amu11.98%32.06 amuA. What is its empirical formula? (Enter 1 if thecorresponding subscript is 1.)C16 H9 N4 Na 3S2B. What is the empirical mass of thecompound? 534.5g/molC. What is its molecular formula? (Enter 1 if thecorresponding subscript is 1.)С 16 Но N4Na 309 S2

Answered: Image /qna-images/answer/0241dd50-d4e9-411a-8219-122caad2df3f.jpg

A. What is its empirical formula? (Enter 1 if the corresponding subscript is 1.) C 16 H9 N4 Na 3 S2 3. What is the empirical mass of the compound? 534.5 g/mol C. What is its molecular formula? (Enter 1 if the corresponding subscript is 1.)

A. What is its empirical formula? (Enter 1 if the corresponding subscript is 1.) C 16 H9 N4 Na 3 S2 3. What is the empirical mass of the compound? 534.5 g/mol C. What is its molecular formula? (Enter 1 if the corresponding subscript is 1.)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

One hundred grams of a dye compound is
equivalent to 0.1871 moles. Its percent
composition is shown below:
Percent
Element
Atomic Mass
Composition
35.95%
12.011 amu
H
1.69%
1.008 amu
N
10.49%
14.007 amu
Na
12.92%
22.990 amu
26.97%
15.999 amu
11.98%
32.06 amu
A. What is its empirical formula? (Enter 1 if the
corresponding subscript is 1.)
C16 H9 N
4 Na 3
S2
B. What is the empirical mass of the
compound? 534.5
g/mol
C. What is its molecular formula? (Enter 1 if the
corresponding subscript is 1.)
С 16 Но N4
Na 3
09 S2

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