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AccessLevel Editor 1 #include #include 4 string can_access(vector &user_rights, int min_permission) £ 6 for(int i-0; i user_rights , indicating the privilege level of each user to use some system resource. You are also given int min_permission, which is the minimum permission a user must have to use this resource string p = ""; 7-if(user_rights.at(i) min_permission)í 10 cout << p + "A"; You are to return a string indicating which users can and cannot access this resource. Each character in the return value corresponds to the element of users with the same index. 'A' indicates the user is allowed access, while 'D' indicates the user is denied access 12 13 14 Constraints user_rights will contain between 0 and 50 elements (0 s user_rights.sizeO s 50), inclusive .Each element of user_rights will be between 0 and 100, inclusive min_permission will be between 0 and 100, inclusive Examples 10,1,2,3,4,5 2 Returns: "DDAAAA" Here, the first two users don't have sufficient privileges, but the remainder do Test Submit

Question

I need guidance on this, more so what direction do I take to append to a string and make sure it is returning the string value?

AccessLevel
Editor
1 #include <string>
#include <vector>
4 string can_access(vector<int> &user_rights, int min_permission) £
6 for(int i-0; i < user_rights.sizeO-1 i++)
Problem Statement
In many computer systems and networks, different users are granted
different levels of access to different resources. In this case, you are given
a vector<int> user_rights , indicating the privilege level of each user to
use some system resource. You are also given int min_permission, which
is the minimum permission a user must have to use this resource
string p = "";
7-if(user_rights.at(i) < min_permission)1
cout << p + "D"
else if(user_rights.at(i) > min_permission)í
10
cout << p + "A";
You are to return a string indicating which users can and cannot access
this resource. Each character in the return value corresponds to the
element of users with the same index. 'A' indicates the user is allowed
access, while 'D' indicates the user is denied access
12
13
14
Constraints
user_rights will contain between 0 and 50 elements (0 s
user_rights.sizeO s 50), inclusive
.Each element of user_rights will be between 0 and 100, inclusive
min_permission will be between 0 and 100, inclusive
Examples
10,1,2,3,4,5 2
Returns: "DDAAAA"
Here, the first two users don't have sufficient privileges, but the
remainder do
Test
Submit
help_outline

Image Transcriptionclose

AccessLevel Editor 1 #include <string> #include <vector> 4 string can_access(vector<int> &user_rights, int min_permission) £ 6 for(int i-0; i < user_rights.sizeO-1 i++) Problem Statement In many computer systems and networks, different users are granted different levels of access to different resources. In this case, you are given a vector<int> user_rights , indicating the privilege level of each user to use some system resource. You are also given int min_permission, which is the minimum permission a user must have to use this resource string p = ""; 7-if(user_rights.at(i) < min_permission)1 cout << p + "D" else if(user_rights.at(i) > min_permission)í 10 cout << p + "A"; You are to return a string indicating which users can and cannot access this resource. Each character in the return value corresponds to the element of users with the same index. 'A' indicates the user is allowed access, while 'D' indicates the user is denied access 12 13 14 Constraints user_rights will contain between 0 and 50 elements (0 s user_rights.sizeO s 50), inclusive .Each element of user_rights will be between 0 and 100, inclusive min_permission will be between 0 and 100, inclusive Examples 10,1,2,3,4,5 2 Returns: "DDAAAA" Here, the first two users don't have sufficient privileges, but the remainder do Test Submit

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check_circleAnswer
Step 1

To append the character "D" and "A" into string you can use append(); function of string class.  As you have already declared a string object as p in your code so, all you need to do is use p.append("D") in your if condition as shown below:

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Computer Science

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