Algorithm: Weighted Interval Scheduling & Dynamic Programming (Knapsack, Edit Distance) Give an algorithm in pseudocode that will produce the minimal-cost sequence of edit operations for strings u and v from the array C computed by following algorithm (in picture). Give proofs of correctness and running time for your algorithm.

Algorithm: Weighted Interval Scheduling & Dynamic Programming (Knapsack, Edit Distance) Give an algorithm in pseudocode that will produce the minimal-cost sequence of edit operations for strings u and v from the array C computed by following algorithm (in picture). Give proofs of correctness and running time for your algorithm.

C++ for Engineers and Scientists

4th Edition

ISBN:9781133187844

Author:Bronson, Gary J.

Publisher:Bronson, Gary J.

Chapter2: Problem Solving Using C++using

Section2.3: Data Types

Problem 9E: (Practice) Although the total number of bytes varies from computer to computer, memory sizes of...

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x=[10,1,20,3,6,2,5,11,15,2,12,14,17,18,29] for i in range(0, len(x)): m = x[i] l = i # Finding the minimum value and its location for j in range(i+1, len(x)): if(m >x [j]): m= x[j] l = j # Now we will do the swapping tmpry = m x[l] = x[i] x[i] = tmpry print(x) 8.The code above is written in Python programming language. In this sample, there are many sectors where you can apply knowledge of code refactoring. Mention each criteria where this code lacks and provide appropriate suggestions to improve. (Hint: Code Smells e.g: Naming Convention, Code length, Assertion etc.)
Let A = {c, n, b}, B = {x, y} and C = {0, 1}. Find A)A X B X C B)C X B X A C)B X C X C
(Practice) Although the total number of bytes varies from computer to computer, memory sizes of millions and billions of bytes are common. In computer language, the letter M representsthe number 1,048,576, which is 2 raised to the 20th power, and G represents 1,073,741,824, which is 2 raised to the 30th power. Therefore, a memory size of 4 MB is really 4 times 1,048,576 (4,194,304 bytes), and a memory size of 2 GB is really 2 times 1,073,741,824 (2,147,483,648 bytes). Using this information, calculate the actual number of bytes in the following: a. A memory containing 512 MB b. A memory consisting of 512 MB words, where each word consists of 2 bytes c. A memory consisting of 512 MB words, where each word consists of 4 bytes d. A thumb drive that specifies 2 GB e. A disk that specifies 4 GB f. A disk that specifies 8 GB
Suppose that you are given the following logical statement:¬ P ∧ Q → ¬ R ∨ SBased on our discussion of order of operations, which is the correct way to interpretthis?(a) ¬(P ∧ ((Q → (¬R)) ∨ S))(b) (¬(P ∧ (Q → (¬R)))) ∨ S(c) ((¬P) ∧ (Q → (¬R))) ∨ S(d) (¬P) ∧ ((Q → (¬R)) ∨ S)(e) (¬(P ∧ Q)) → (¬(R ∨ S))(f) ((¬P) ∧ Q) → ((¬R) ∨ S)(g) ((¬P) ∧ (Q → (¬R))) ∨ S(h) ((¬P) ∧ (Q → (¬R))) ∨ S(i) (¬P) ∧ ((Q → (¬R)) ∨ S)(j) ¬((P ∧ Q) → (¬(R ∨ S)))
Let l be a line in the x-yplane. If l is a vertical line, its equation is x = a for some real number a. Suppose l is not a vertical line and its slope is m. Then the equation of l is y = mx + b, where b is the y-intercept. If l passes through the point (x₀, y₀), the equation of l can be written as y - y₀ = m(x - x₀). If (x₁, y₁) and (x₂, y₂) are two points in the x-y plane and x₁ ≠ x₂, the slope of line passing through these points is m = (y₂ - y₁)/(x₂ - x₁). Instructions Write a program that prompts the user for two points in the x-y plane. Input should be entered in the following order: Input x₁ Input y₁ Input x₂
Present a coding technnique that accepts 2 numbers x,y that will result into a transformation L: R^2 -> R^2 Example: L(x,y) = (x-y,x+y) .
What is the final value of x?
Practice 3: Let’s compile following C sequence for MIPS and run on the emulator: int divide(int N, int M) { // map q and i to $s2 and $s3 int q = 0; int i = N; while(i > 0) { q += 1; i = i - M; } return q; } int multiply(int N, int M) { // map sum and i to $s0 and $s1 int sum = 0; for(int i = 0; i < N; ++i) { sum += M; } return sum; } int main() { // map a, b, c, k, and j to $s0, $s1, $s2, $s3, and $s4 int a = 4; int b = 5; int c = 120; int k = multiply(a, b); int j = divide(c, k); } Make sure multiply procedure properly gets backup of $s0 to $s4. Verify that after running this sequence: • value of S0 is (4)10 • value of S1 is (5)10 • value of S2 is (120)10 • value of S3 is (20)10 • value of S4 is (6)10 When ready, copy your MIPS assembly code from emulator and save as a text file.
Suppose you have a finite state machine that accepts bit strings divisible by 11. The FSM has 11 states R0, R1, ... , R10, each corresponding to the remainder when dividing by 11. Input is fed to the FSM one bit at a time from left to right, the same way we did in our in-class examples. If the machine is currently in state R7, an input of 1 should transition it to which state? Type the subscript only of the new state. Your answer should be an integer between 0 and 10, inclusive.
v = (3, 5)print(v)p, q = v[0], v[1]r = p + qif r % 2 == 0:p = p + r - 5q = q + r - pr = r + 1v = (p, q)print(v)else:p = p - 1q = q - 1if r % 3 != 0:v = (p, q)print(v)else:p, q = q, pv = (p, q)print(v)
Transform the following sentences to CNF. 1. ꓯ x (P(x) ꓦ Q(x)) → R(x) 2. ꓯ x ꓯ y ꓯ z (A(x,y) ꓥ A(y,z)) → A(x,z) 3. ꓯ x ꓯ y ꓱ z P(x,z) ꓥ Q(y,z) 4. ꓯ x ⌐ [(P(x) ꓥ Q(x)) ꓦ (R(x) ꓥ S(x))]
Let l be a line in the x-y plane. If l is a vertical line, its equation is x 5a for some real number a. Suppose l is not a vertical line and its slope is m. Then the equation of l is y 5mx 1b, where b is the y-intercept. If l passes through the point (x0, y0,), the equation of l can be written as y 2y0 5m(x 2x0 ). If (x1, y1) and (x2, y2) are two points in the x-y plane and x1 ≠ x2, the slope of line passing through these points is m 5(y2 2y1 )/(x2 2x1 ). Write a program that prompts the user two points in the x-y plane. The program outputs the equation of the line and uses if statements to determine and output whether the line is vertical, horizontal, increasing, or decreasing. If l is a non-vertical line, output its equation in the form y 5mx 1b.