All functions should belong to a template class. Functions' code should be efficient as well as correct. For all linked lists, first points to the first node and it is the only pointer in the list (there is no last). For circular sorted lists first points to the largest element. Write a function, to be included in an unsorted linked list class, called replace item, that will receive two parameters, one called olditem, the other called newitem. The function will replace all occurrences of olditem with newitem ( if olditem exists !! ) and it will return the number of replacements done. Write a function, to be included in a sorted linked list class, called printPosition, that will receive a parameter and print its position within the list ( position 1 if first, position 2 if second...). If the item is not in the list, specify it in a printing. Consider efficiency. Write a function, to be included in an unsorted linked list class, called getLargest, that will return the largest item in the list.
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- Add a new public member function to the LinkedList class named reverse() which reverses the items in the list. You must take advantage of the doubly-linked list structure to do this efficiently as discussed in the videos/pdfs, i.e. swap each node’s prev/next pointers, and finally swap headPtr/tailPtr. Demonstrate your function works by creating a sample list of a few entries in main(), printing out the contents of the list, reversing the list, and then printing out the contents of the list again to show that the list has been reversed. Note: your function must actually reverse the items in the doubly-linked list, not just print them out in reverse order! Note: we won't use the copy constructor in this assignment, and as such you aren't required to update the copy constructor to work with a doubly-linked list. This is what I have so far but its not working! template<class ItemType>void LinkedList<ItemType>::reverse(){ Node<ItemType>*curPtr,*prev,*next;…Write a void function that takes a linked list of integers and removes all the duplicate elements from the list. The function will have one call-by-reference parameter that is a pointer to the head of the list. After the function is called, this pointer will point to the head of a linked list that has the nodes that have all the distinct integers. Place your function in a suitable test program.Write a function that gets a linked list of ints, and reverses it. For example - on input 1 -> 2 -> 3 -> 4, after the function finishes the execution, the list becomes 4 -> 3 -> 2 -> 1 - If the list has one element, then it doesn’t change - If the list is empty, then it doesn’t change You may use the data fields in the struct and the functions provided in LL.h and LL.c. // reverses a linked list void LL_reverse(LL_t* list); Test for the Function: void test_q3() { LL_t* lst = LLcreate(); LL_add_to_tail(lst, 1); LL_add_to_tail(lst, 3); LL_add_to_tail(lst, 8); LL_add_to_tail(lst, 4); LL_add_to_tail(lst, 3); LL_reverse(lst); intcorrect[] = {3,4,8,3,1}; inti; node_t* n = lst->head; for(i=0;i<5;i++) { if (n==NULL) { printf("Q3 ERROR: node %d==NULL unexpected\n", i); return; } if (n->data != correct[i]) { printf("Q3 ERROR: node%d->data==%d, expected %d\n", i, n->data, correct[i]); return; } n = n->next; } if (n==NULL) printf("Q3 ok\n"); } Support…
- Write a function that gets a linked list of ints, and reverses it. For example - on input 1 -> 2 -> 3 -> 4, after the function finishes the execution, the list becomes 4 -> 3 -> 2 -> 1 - If the list has one element, then it doesn’t change - If the list is empty, then it doesn’t change You may use the data fields in the struct and the functions provided in LL.h and LL.c. // reverses a linked list void LL_reverse(LL_t* list); Test for the Function; void test_q3() { LL_t* lst = LLcreate(); LL_add_to_tail(lst, 1); LL_add_to_tail(lst, 3); LL_add_to_tail(lst, 8); LL_add_to_tail(lst, 4); LL_add_to_tail(lst, 3); LL_reverse(lst); intcorrect[] = {3,4,8,3,1}; inti; node_t* n = lst->head; for(i=0;i<5;i++) { if (n==NULL) { printf("Q3 ERROR: node %d==NULL unexpected\n", i); return; } if (n->data != correct[i]) { printf("Q3 ERROR: node%d->data==%d, expected %d\n", i, n->data, correct[i]); return; } n = n->next; } if (n==NULL) printf("Q3 ok\n"); } Support File…Extend the class linkedListType by adding the following operations:a. Write a function that returns the info of the kth element of the linkedlist. If no such element exists, terminate the program.b. Write a function that deletes the kth element of the linked list. If nosuch element exists, output an appropriate message. Provide the definitions of these functions in the class linkedListType. Also writea program to test these functions. (Use either the classunorderedLinkedList or the class orderedLinkedList to testyour function.) Note: Code in c++Write a function that takes a list removal(L), delete from it all the elements whose indicesare divisible by 3. And return the resulting list after removing unwanted elements.Example:>>>removal(['A', 'B', 'C', 'D', 'E'])['B', 'C','E'
- Sets are collections (1) without defined order and (2) not allowing duplication. Multisets, also called “bags” are collections without defined order but which permit duplication, i.e., more than one element. We define the function #(a B) to be the number of occurrences of the element a in the bag B. For example, #(1, [1 1 2 3 4 4 5]) is 2 and #(5, [1 1 2 3 4 4 5]) = 1. sum : List × List -> ListThis function should take as arguments two lists representing bags and should return the list representing the list resulting from simply appending the input lists together. Racket code only please. No loops Allowed: 1. define, let2. lambda3. cons, car, cdr, list, list?, append, empty?, length, equal?4. and, or, not5. if, cond7. +, -, /, * Thank you!You are given the pointer to the head node of a linked list and an integer to add to the list. Create a new node with the given integer. Insert this node at the tail of the linked list and return the head node of the linked list formed after inserting this new node. The given head pointer may be null, meaning that the initial list is empty. Function Description Complete the insertNodeAtTail function in the editor below. insertNodeAtTail has the following parameters: SinglyLinkedListNode pointer head: a reference to the head of a list int data: the data value for the node to insert Returns SinglyLinkedListNode pointer: reference to the head of the modified linked list Input Format The first line contains an integer , the number of elements in the linked list.The next lines contain an integer each, the value that needs to be inserted at tail. Constraints Sample Input STDIN Function ----- -------- 5 size of linked list n = 5 141 linked list data values…A linked list is said to contain a cycle if any node is visited more than once while traversing the list. Given a pointer to the head of a linked list, determine if it contains a cycle. If it does, return . Otherwise, return . Example refers to the list of nodes The numbers shown are the node numbers, not their data values. There is no cycle in this list so return . refers to the list of nodes There is a cycle where node 3 points back to node 1, so return . Function Description Complete the has_cycle function in the editor below. It has the following parameter: SinglyLinkedListNode pointer head: a reference to the head of the list Returns int: if there is a cycle or if there is not Note: If the list is empty, will be null. Input Format The code stub reads from stdin and passes the appropriate argument to your function. The custom test cases format will not be described for this question due to its complexity. Expand the section for the main function and review the…
- Sets are collections (1) without defined order and (2) not allowing duplication. Multisets, also called “bags” are collections without defined order but which permit duplication, i.e., more than one element. We define the function #(a B) to be the number of occurrences of the element a in the bag B. For example, #(1, [1 1 2 3 4 4 5]) is 2 and #(5, [1 1 2 3 4 4 5]) = 1. sum : List × List -> List This function should take as arguments two lists representing bags and should return the list representing the list resulting from simply appending the input lists together. Racket code only please. No loops Allowed: 1. define, let2. lambda, curry3. cons, car, cdr, list, list?, append, empty?, length, equal?4. and, or, not5. if, cond6. map, append-map, andmap, ormap, filter, apply7. +, -, /, * Thank you!There’s a somewhat imperfect analogy between a linked list and a railroad train, where individual cars represent links. Imagine how you would carry out various linked list operations, such as those implemented by the member functions insertFirst(), removeFirst(), and remove(int key) from the LinkList class in this hour. Also implement an insertAfter() function. You’ll need some sidings and switches. You can use a model train set if you have one. Otherwise, try drawing tracks on a piece of paper and using business cards for train cars.Consider the following function that takes reference to head of a Doubly Linked List as parameter. Assume that anode of doubly linked list has previous pointer as prev and next pointer as next.void fun(struct node **head_ref){struct node *temp = NULL;struct node *current = *head_ref;while (current != NULL){temp = current->prev;current->prev = current->next;current->next = temp;current = current->prev;}if(temp != NULL )*head_ref = temp->prev;}Assume that reference of head of following doubly linked list is passed to above function 1 <--> 2 <--> 3 <--> 4 <--> 5 <-->6. What should be the modified linked list after the function call? Note: solve as soon as possible