OTribbles (fictional space creatures) have four, with three independentlyassorting loc. that all shows complete dominance controlling thephenotype as follows:• Locus P controlsfur curl, with W=way fur & straight furfour pigment, with P-pink fur + p=blue four• Locus I controls pigment deposition and withincts with loensP, with D = four color is expressed, and d= no pigment deposited,resulting in a black tribblecentralsSuppose that a crass- occursbetogeeni posents thatWPDphenotype individual withcoere frue -bocceding (10PD) x upD)• an• acompletely heterozygous individualWhat are the probabilties of the follow y phenstypes ?Black TribbleBlue tribble withwavyhair

Name: OTribbles (fictional space creatures) have four, with three independe
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Description: OTribbles (fictional space creatures) have four, with three independentlyassorting loc. that all shows complete dominance controlling thephenotype as follows:• Locus P controlsfur curl, with W=way fur & straight furfour pigment, with P-pink fur + p=

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• am WTD phenotype individual with parents that Loere frue - breeding (LOPD) x up() completely heterozygous individual . a

Concepts of Biology

1st Edition

ISBN:9781938168116

Author:Samantha Fowler, Rebecca Roush, James Wise

Publisher:Samantha Fowler, Rebecca Roush, James Wise

Chapter8: Patterns Of Inheritance

Section: Chapter Questions

Problem 11RQ: The ABO blood groups in humans are expressed as the IA,IB and i alleles. The IAallele encodes the A...

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Mendel's concept of dominance states that in a genotype where two different alleles of a locus are present, only the trait encoded by the dominant allele is observed. Give a molecular explanation for dominance, i.e. explain intracellular molecular events that can result in what we observe as dominance on a phenotypic level. Use the gene that encodes seed shape in peas as an example, where roun(R) is dominant over wrinkled(r), to explain how RR and Rr plants can have the same phenotype.
In rabbits, fur colour can be either grey, black or blotchy. Blotchy is present as grey and black spotspresent in no specific pattern. Males are almost always either grey or black, while females can begrey, black or blotchy. However, a male individual is found that shows the blotchy pattern, and youexpect a non-disjunction event might be to blame. Explain the inheritance of coat colour in rabbits,and also provide an explanation for the blotchy male.
In humans, free ear lobes (E) is dominant over attached ear lobes (e), and brown eyes (B) is dominant over blue eyes (b). A man with free ear lobes and brown eyes married a woman with attached ear lobes and brown eyes. Of four children, one has free ear lobes and brown eyes, one has free ear lobes and blue eyes, one has attached ear lobes and brown eyes, and one has attached ear lobes and blue eyes. Determine the genotypes of both parents.
Red-green colorblindness is determined in humans by a single X-linked locus. Colorblind males are XbY, and males with normal vision are XBY. XB is dominant, so XBXB and XBXb females have normal vision, while XbXb females are colorblind. Typically, 8% of males are red-green colorblind. Assuming H-W equilibrium, what percentage of females is typically colorblind?
There are two genes that determine the coat colour expression in some dogs: eumelanin and merle. These genes are located on two separate chromosomes. For the eumelanin gene, black coat colour (E) is dominant over red coat colour (e). The merle gene controls the degree to which these coat colours are expressed through incomplete dominance. The following table describes the merle gene expression. Genotype Phenotype MM White Mm Half colour (Grey or light red) mm Full colour (Black or Red) Two dogs heterozygous for both traits were crossed. What phenotypic ratio is expected in the F1 generation? Answer: Phenotype: White Grey Black Light Red Red
Trait X displays 98% concordance in both monozygotic and dizygotic twins. Do these concordances suggest that trait X is influenced by (a) genetic factors; (b) environmental factors; or (c) both genetic and environmental factors? Explain your reasoning
Let’s look at hair texture. Some people have curly hair, some have straight hair and some express a traitthat is in-between (Incomplete Dominance), or wavy hair. Therefore curly and straight are bothhomozygous and wavy is the expression of the heterozygous condition. Instead of using capital and lowercase letters, we’ll add a prime (`) to the letter. This is because one is not dominant over the other, andthey will both contribute to the phenotype. We can use H to indicate curly hair and H` to indicate straighthair.Given this information, complete the square: Parent Phenotype(appearance) Genotype(alleles) 1 Curly hair HH 2 Straight hair H'H' Do you remember where the alleles of each parent go?Parents: Offspring: Genotypes: Phenotypes: What are the potential phenotypes and genotypes of the offspring?
There are two genes that determine the coat colour expression in some dogs: eumelanin and merle. These genes are located on two separate chromosomes. For the eumelanin gene, black coat colour (E) is dominant over red coat colour (e). The merle gene controls the degree to which these coat colours are expressed through incomplete dominance. The following table describes the merle gene expression. Genotype Phenotype MM White Mm Half colour (Grey or light red) mm Full colour (Black or Red) A grey dog that is heterozygous for the eumelanin gene mates with a light red dog. 1. What is the probability they would have a grey puppy? 2. What is the probability they would have a grey or light red puppy?
A recessive epistasis cross gives in the F2 a 9:3:4 phenotypic ratio. What is the expected phenotypic ratio when the F1 (BbEe) is crossed with the double recessive homozygote (bbee)? Keeping in mind ee masks the expression of B.
E. W. Lindstrom crossed two corn plants with green seedlings and obtained the following progeny: 3583 green seedlings, 853 virescentwhite seedlings, and 260 yellow seedlings . Q. Is there epistasis among the genes that determine color in the corn seedlings? If so, which gene is epistatic and which is hypostatic?
Two hedgehog parents are heterozygous at the spiny locus, each with genotype Ss. This locus affects the length of the individuals’ spines, which ranges from 1 cm in SS homozygotes to 3 cm in ss homozygotes.Inheritance of spine length in this family is entirely due to the spiny locus and it exhibits additivity. Remember that development of spines depends on thousands of genes, but we’re only considering this one gene because it’s the one that varies in a way that affects spine length in this family. a) List all of the phenotypes we could observe among offspring of these Ss heterozygote parents. b) What’s the probability that an offspring of these heterozygous parents is an SS homozygote? c) If the parents have exactly two offspring, what is the probability that the two hedgehog kids have no alleles in common? In other words, what’s the probability that one kid is SS and the other ss?
In cats, gray hair (GG) is dominant to white hair (gg). Also in cats, black eyes (BB) are dominant to red eyes (rr).What are the phenotypes of cats that have the following genotypes? (2) Ggbb (2) ggBB (3) ggbb (4) GgBb