Ammoniacal nitrogen can be determined by treatment of the sample with chloroplatinic acid; the product is slightly soluble ammonium chloroplatinate: H₂PtCl 6 + 2 NH4+* --> (NH4)2PtCl6 + 2H+ The precipitate decomposes on ignition, yeilding metallic platinum and gaseous products: (NH4)2PtCl6 --> Pt (s) + 2 Cl2 (g) + 2 NH3 (g) + 2 HCI (g) Calculate the percentage of ammonium in a sample if 0.2235-g gave rise to 0.8218 - g of platinum (At Mass = 195.08 g/mol). The molecular weight of ammonia is 17.0306 g/mol.
Ammoniacal nitrogen can be determined by treatment of the sample with chloroplatinic acid; the product is slightly soluble ammonium chloroplatinate: H₂PtCl 6 + 2 NH4+* --> (NH4)2PtCl6 + 2H+ The precipitate decomposes on ignition, yeilding metallic platinum and gaseous products: (NH4)2PtCl6 --> Pt (s) + 2 Cl2 (g) + 2 NH3 (g) + 2 HCI (g) Calculate the percentage of ammonium in a sample if 0.2235-g gave rise to 0.8218 - g of platinum (At Mass = 195.08 g/mol). The molecular weight of ammonia is 17.0306 g/mol.
Chapter12: Gravimetric Methods Of Analysis
Section: Chapter Questions
Problem 12.20QAP
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