Answered: Ammonium carbamate, (NH4)(OCONH2) (FW…

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter5: Gases

Section: Chapter Questions

Problem 5.62PAE: 62 Ammonium dinitramide (ADN), NH4N(NO2)2, was considered as a possible replacement for aluminium...

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Question

Ammonium carbamate, (NH4)(OCONH2) (FW 78.071), is unstable, decomposing into ammonia (FW 17.03) and carbon dioxide (FW 44.01).

(NH4)(OCONH2) (s) -> 2 NH3 (g) + CO2 (g)

A 5.00 g portion of solid ammonium carbamate was placed in a 5.00-L container. The air was removed from the sealed container and the reaction shown above was allowed to reach equilibrium at 25 oC.
Once equilibrium was reached, the pressure in the container was found to be 0.27 atm.

Calculate KP for this reaction at 25 oC.

Expert Solution

Step 1

Recall the given reaction

$(N H_{4}) (O C O N H_{2}) (s) \to 2 N H_{3} (g) + C O_{2} (g)$

Write expression of K_p

$K_{p} = {(P_{N H_{3}})}^{2} \times (P_{C O_{2}}) (A s P_{(N H_{4}) (O C O N H_{2}) (s)} = 1)$

A 5.00 g of solid ammonium carbamate was placed in 5.00 L container

When the system reaches equilibrium total pressure of the container is 0.27 atm

Now in equilibrium only products ammonia and carbon dioxide remain in gaseous state in the ratio of 2:1

So Partial pressure of NH₃

$P_{N H_{3}} = \frac{2}{3} \times (0.27) a t m P_{N H_{3}} = 0.18 a t m$

and partial pressure of CO₂

$P_{C O_{2}} = \frac{1}{3} (0.27) a t m P_{C O_{2}} = 0.09 a t m$

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