An empty steel container is filled with 0.0290 atm of HF. The system is allowed to reach equilibrium. If Kp = 2.76 for the reaction below, what is the equilibrium partial pressure of H2? 2 HF (g) = H2 (g) + F2 (g)
An empty steel container is filled with 0.0290 atm of HF. The system is allowed to reach equilibrium. If Kp = 2.76 for the reaction below, what is the equilibrium partial pressure of H2? 2 HF (g) = H2 (g) + F2 (g)
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter18: Principles Of Chemical Reactivity: Entropy And Free Energy
Section18.1: Spontaneity And Energy Transfer As Heat
Problem 1RC: 1. A process is spontaneous in the direction that moves it
away from equilibrium
toward equilibrium
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Step 1
Given,
2 HF (g) ⇌ H2 (g) + F2 (g)
Equilibrium constant (Kp) = 2.76
Initial partial pressure of HF = 0.0290 atm
Equilibrium partial pressure of H2 = ?
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