An engine goes through the reversible cycle shown. The engine contains n= 8 mol of a diatomic ideal gas with specific heat at constant volume of 20.8 J/(K mol). The process 3 ->1 is an isothermal process (recall the work done during such a process is nRT In(VIVF). The other two process types can be inferred from the diagram. At point 3, the pressure of the gas is 12 105 Pa, its temperature is 1530 degrees celsius, and its volume is 0.1 m3. At point 2, the temperature of the gas is 30 degrees celsius. Fill out the following chart for this thermodynamic cycle with the numerical values of the ingredients of the 1st Law of Thermodynamics for each of the three processes. QG) wl3) AE(3) 142 243 371 What is the efficiency of this engine? Does this engine violate the 2nd Law of Thermodynamics?

Principles of Physics: A Calculus-Based Text
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Chapter18: Heat Engines, Entropy, And The Second Law Of Thermodynamics
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An engine goes through the reversible cycle shown. The engine contains n = 8 mol of a diatomic ideal gas with specific heat at constant volume of 20.8 J/(K mol). The process 3 -> 1 is an isothermal process (recall the work done during such a process is nRT ln(Vi/Vf)). The other two process types can be inferred from the diagram. At point 3, the pressure of the gas is 12 105 Pa, its temperature is 1530 degrees celsius, and its volume is 0.1 m3. At point 2, the temperature of the gas is 30 degrees celsius.

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An engine goes through the reversible cycle shown. The engine contains n= 8 mol of a
diatomic ideal gas with specific heat at constant volume of 20.8 J/(K mol). The process 3 ->1 is
an isothermal process (recall the work done during such a process is nRT In(VIVF). The other
two process types can be inferred from the diagram. At point 3, the pressure of the gas is 12
105 Pa, its temperature is 1530 degrees celsius, and its volume is 0.1 m3. At point 2, the
temperature of the gas is 30 degrees celsius.
Transcribed Image Text:An engine goes through the reversible cycle shown. The engine contains n= 8 mol of a diatomic ideal gas with specific heat at constant volume of 20.8 J/(K mol). The process 3 ->1 is an isothermal process (recall the work done during such a process is nRT In(VIVF). The other two process types can be inferred from the diagram. At point 3, the pressure of the gas is 12 105 Pa, its temperature is 1530 degrees celsius, and its volume is 0.1 m3. At point 2, the temperature of the gas is 30 degrees celsius.
Fill out the following chart for this thermodynamic cycle with the numerical values
of the ingredients of the 1st Law of Thermodynamics for each of the three processes.
QG)
wl3)
AE(3)
142
243
371
What is the efficiency of this engine?
Does this engine violate the 2nd Law of Thermodynamics?
Transcribed Image Text:Fill out the following chart for this thermodynamic cycle with the numerical values of the ingredients of the 1st Law of Thermodynamics for each of the three processes. QG) wl3) AE(3) 142 243 371 What is the efficiency of this engine? Does this engine violate the 2nd Law of Thermodynamics?
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