An enzyme catalyzes a reaction with a K of 7.50 mM and a Vmax of 4.15 mMs. Calculate the reaction velocity, o, for eachsubstrate concentration.[S] = 1.75 mMMM-s-1[S] = 7.50 mM[S] = 11.0 mMDOmM-smM-s Determine the value of the turnover number of the enzyme invertase, given that Rmax (Vmax) for invertase is15.8 mmol. L-¹ min and [E], = 4.7 μmol L. Invertase has a single active site.*.turnover number=min-¹

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Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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An enzyme catalyzes a reaction with a Km of 7.50 mM and a Vmax of 4.15 mMs. Calculate the reaction velocity, Do, for each substrate concentration. [S] = 1.75 mM mM-si [S] = 7.50 mM [S] = 11.0 mM DO: Do 110: mM-s mM-s