An experiemnt was performed for the synthesis and reaction of a grignard reagent. Why was the yield of the product diphenyl tertiary alcohol low?
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An experiemnt was performed for the synthesis and reaction of a grignard reagent. Why was the yield of the product diphenyl tertiary alcohol low?
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- Lactated Ringer’s/5% Dextrose solution contains: 6 g/L of Sodium Chloride (NaCl MW 58.5) 3.1 g/L of Sodium Lactate (C3H5O3Na MW 112) 0.3g/L of Potassium Chloride (KCl MW 74.5) 0.2g/L of Calcium Chloride (CaCl2•2H2O MW 147) 50g/L of Dextrose (C6H12O6 MW 180) You receive an order to increase the Potassium ion concentration to 0.045 mEq/mL. How many mL of 14.9% Potassium chloride injection should be added to 1L of the above solution to increase the potassium ion concentration to 0.045 mEq/mL ____________________mL 14.9% KCl injectionCalculate the amount of phycocyanin in Sample 1 in mg where A620=0.211 and A650=0.086, taking into account the dilution factor as per question 6 (100ul), and the total volume of extract as per question 4 (140ml) . Note your answer to 2 decimal placesCalculate the amount of phycocyanin in Sample 1 in mg where A620=0.233 and A650=0.061, using a dilution factor of 100, and a total volume of extract as 45 mL. Note your answer to 2 decimal places.
- Can you tell me if I am doing this correctly? For the thermoeter correction, we are given that: literature value of standard - experimental value of standard at end of melting temperature. I found online that the melting range of pure acetanilide is 113-115. From there I calculated the therometer correction. Substance Melting Point Range Begins/Ends (oC) Interval of Melting (oC) Thermometer Correction for Calibration Data (oC) Corrected Melting Point (oC) Crystallized acetanilide Trial #1 111.9 – 112.9 1.0 2.1 Crystallized acetanilide Trial #2 111.0 – 112.3 1.3 2.7 Crude acetanilide 112.9-115.4 2.5 -0.4 Acetanilide standard Lot # 115.6-116.5 0.9 -1.5 N/AMass of crude Acetanilide = 0.508 Mass of filter paper = 0.800g Filter paper + pure Acetanilide = 1.153g Mass of pure Acetanilide = ? % recovery = ? Mpt of recrystallized Acetanilide =112 C – 114 C Mpt of crude Acetanilide = 97 C – 110 CAcetaminophen or paracetamol, the active ingredient in many pain killers absorbs in the UV range with a λmax at 250 nm in neutral solutions (methanol usually). Its extinction coefficient is 14 mM-1cm-1. Each commercially available tablet (Tylenol, Panadol or Herron) contains 500 mg paracetamol. Its molecular weight is 151.1. Using this information, calculate the dilution required to analyse the concentration of paracetamol in a commercially available paracetamol tablet. Start by dissolving the tablet in 100 mL methanol. Show working out.
- A brewed tea brand sample was subjected to solvent extraction to extract caffeine. The cup of tea measuring 200 mL was extracted with petroleum ether. With KD = 20.0 (caffeine in pet ether-water), the % caffeine (194.10) extracted after 3 extractions with a total of 75.0 mL pet ether used is: A. 97.7% B. 28.6% C. 71.4% D. 2.33%Q) water hardness of each trial and average ppm with calculation, please. Hard Water Trial 1 Hard Water Trial 2 Hard Water Trial 3 Initial Syringe Reading 1.0ml 1.0ml 1.0ml Final Syringe Reading 0.88ml 0.84ml 0.85ml Volume of EDTA Consumed 0.12ml 0.16ml 0.15ml Water Hardness ppm CaCO3 Average ppm1-A bottle of Na2EDTA.2H2O is labeled with an assay of 100.5%, what is this implied?What is the result of heating to 100 ºC?
- MAKE A METHODOLOGY : MATERIALS/ REAGENTS WITH SCHEMATIC DIAGRAM . THE PICTURE UPLOADED SERVES AS A GUIDE, DO THE SAME THING BASED FROM THE PIC. Procedure: Place 20 drops of each of 0.2M CuSO4 in a centrifuge tube. Then add 5 drops of freshly prepared 6M (NH4)2S to each centrifuge tube. Record your observation. Centrifuge the mixtures for 3 mins. and decant the supernatant liquid. Add 10 drops of DI water and 10 drops of 6M HNO3. Stir and boil the mixture in a hot water bath for 5 mins. centrifuge the mixture for 3 mins. Decant the supernatant solution from procedure 3. Discard the To each of the supernatant liquid, add 6 drops of 6M H2SO4. Allow themixtures to cool and 5 drops of DI water. To the mixtures in procedure 4, add few drops of concentrated NH3 until the solution becomes basic. Confirm using a litmus paper. Record your observation. Add 1 drop of 5M NaOH and 1 drop of 0.1 M SnCl2 to the centrifuge tube containing Bi3+ ion , centrifuge and decant the supernatant liquid. To…5.00 mL of stock solution is diluted to 25.00 mL, producing solution ALPHA. 10.00 mL of solution ALPHA is diluted to 25.00 mL, resulting in solution BETA. 10.00 mL of solution BETA is then diluted to 25.00 mL, producing solution GAMMA. dilution factor for ALPHA from stock solution = 0.167 dilution factor for BETA from ALPHA solution = 0.0476 part c and d?Melting point: 122-123 experimental product melting point: 120 mass of starting material: 1.04 mass of product: 0.85g what is limiting reagent and percent yield?