an you select the answers in each bracket? The imine functionality is similar to [ carbonyl / nucleophile / acid / amine] meaning that it can react as [ electrophile / nucleophile / proton acceptor / proton donor ] if paired with [ electrophile / nucleophile / acid / base ] . Similarly to, [ carbonyls / enols / alkenes/ bases ], enamines will undergo alpha substitutions when paired with [ electrophile / nucleophile / acid / base ] .

an you select the answers in each bracket? The imine functionality is similar to [ carbonyl / nucleophile / acid / amine] meaning that it can react as [ electrophile / nucleophile / proton acceptor / proton donor ] if paired with [ electrophile / nucleophile / acid / base ] . Similarly to, [ carbonyls / enols / alkenes/ bases ], enamines will undergo alpha substitutions when paired with [ electrophile / nucleophile / acid / base ] .

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter19: Eas: Electrophilic Aromatic Substitution

Section: Chapter Questions

Problem 38CTQ

See similar textbooks

Similar questions

Can you choose the right answer in each bracket? Inside the box (final step), [ester / ketone / amine / amide] functionality acts as a [ electrophile / nucleophile / acid / base] to attack [ester / ketone / amine / amide] functionality, which serves as a [ electrophile / nucleophile / acid / base]. These will react [intramolecularly / intermoleculary] to afford the [imine/ enamine/ amine / amide] functionality in the target compound.
Amides are weak nucleophiles but their conjugate bases are string nucleophiles. The amide drawn below can be deprotonated in four possible locations, labeled A-D but two are considerably more acidic than the others. Draw the two different Bronsted Lowery acid/base reactions (using HO- as the BL base) showing the deprotonation at these two locations. Draw all RS with arrows for both conjugate bases but no hybrids. Based on your resonance analysis which location is the most acidic in the molecule? Why is it most acidic? Amides can also be protonated by a strong acid in two different locations. Draw two different conjugate acids for the amide above as well as RS with arrows for each. Based on your resonance analysis which atom is the most basic in an amide?
Please answer this NEATLY, COMPLETELY, and CORRECTLY for an UPVOTE. Arrange the intermediates below in order of increasing basicity:
In benzoic acid, when it has a deactivating group in position "para" (relative to carboxylate position) , it attracts electrons towards it, weakening the acid and an activator pushes the electrons making the acid stronger.What happens to this benzoic acid if it has a substituent at the "meta" or "ortho" position as an activator or a deactivator? I need an explanation of what happens in each case please
For the given molecule, highlight any nucleophilic sites in red and any electrophilic sites in blue.
Some of the groups pre-bonded to an aromatic ring cause electrophilic aromatic substitution to occur mainly at the ortho and para sites. Others lead to the meta location. Is that true or false?
In paragraph/essay form:Provide an explanation (in detail) on how base catalysts speed up nucleophilic reactions of carbonyl compounds.
Can you please answer what the missing compound A and B are?
A proton transfer reaction can occur when a carbonyl compound is placed in an aqueous acidic solution. Water and a charged conjugate acid are produced. The resulting organic compound is resonance stabilized.Draw the curved arrows for the proton transfer and draw both resonance-stabilized organic products in the appropriate boxes. Be sure to include all lone pairs and nonzero formal charges. Do not draw the water product.
Fluoride ion is usually a poor leaving group because it is not very polarizable. Fluorideserves as the leaving group in the Sanger reagent (2,4-dinitrofluorobenzene), used inthe determination of peptide structures (Chapter 24). Explain why fluoride works as aleaving group in this nucleophilic aromatic substitution, even though it is a poor leavinggroup in the SN1 and SN2 mechanisms.
In electrophilic aromatic substitution, a group attached to the aromatic ring does not affect ring reactivity. Is that true or false?